The parallel plates shown in the figure carry equal amounts of opposite type charge and are a distance, d = 1.2 cm apart. The electric potential on plate B is 620-V higher than that on plate A. The figure also shows an equipotential contour (dashed line) that is located a distance, x = 0.8 cm, from plate B. of 2) The Electric Field (a) What can you conclude about the electric potential on the two plates? OVA = 0 V and VB = 620 V E= OVA = -310 and VB = 310 V A (b) Determine the magnitude and direction of the electric field in the region between the two plates. V/cm and it points ---Select--- V OVB - VA = 620 V (c) What is the potential difference between plate B and the equipotential contour (dashed line)? VB - Vx= x

The parallel plates shown in the figure carry equal amounts of opposite type charge and are a distance, d = 1.2 cm apart. The electric potential on plate B is 620-V higher than that on plate A. The figure also shows an equipotential contour (dashed line) that is located a distance, x = 0.8 cm, from plate B. of 2) The Electric Field (a) What can you conclude about the electric potential on the two plates? OVA = 0 V and VB = 620 V E= OVA = -310 and VB = 310 V A (b) Determine the magnitude and direction of the electric field in the region between the two plates. V/cm and it points ---Select--- V OVB - VA = 620 V (c) What is the potential difference between plate B and the equipotential contour (dashed line)? VB - Vx= x