The parallel plates shown in the figure carry equal amounts ofopposite type charge and are a distance, d = 1.2 cm apart.The electric potential on plate B is 620-V higher than that on plate A.The figure also shows an equipotential contour (dashed line)that is located a distance, x = 0.8 cm, from plate B.(1 of 2) The Electric Field(a) What can you conclude about the electric potential on the two plates?OVA = 0 V and VB = 620 VOVA = -310 and VB = 310 VE =AOVB - VA = 620 V(b) Determine the magnitude and direction of the electric field in the region between the two plates.V/cm and it points ---Select---(c) What is the potential difference between plate B and the equipotential contour (dashed line)?VB - Vx=dXB

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