Two charges of q, = 1.6 µC and q, = -2.6 µC are d = 0.30 m apart at two vertices of an equilateral triangle as in the figure below. d d + d 92 (a) What is the electric potential due to the 1.6-µC charge at the third vertex, point P? 4.8E4 (b) What is the electric potential due to the -2.6-µC charge at P? |-7.8E4 V (c) Find the total electric potential at P. -3E4 (d) What is the work required to move a 3.4-µC charge from infinity to P? |-1.02 Your response is off by a multiple of ten. J

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Chapter1: Units, Trigonometry. And Vectors
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Two charges of q1
1.6 µC and q2
= -2.6 µC are d = 0.30 m apart at two vertices of an equilateral triangle as in the figure below.
d
92
(a) What is the electric potential due to the 1.6-µC charge at the third vertex, point P?
4.8E4
V
(b) What is the electric potential due to the -2.6-µC charge at P?
|-7.8E4
V
(c) Find the total electric potential at P.
-ЗЕ4
V
(d) What is the work required to move a 3.4-µC charge from infinity to P?
-1.02
Your response is off by a multiple of ten. J
Transcribed Image Text:Two charges of q1 1.6 µC and q2 = -2.6 µC are d = 0.30 m apart at two vertices of an equilateral triangle as in the figure below. d 92 (a) What is the electric potential due to the 1.6-µC charge at the third vertex, point P? 4.8E4 V (b) What is the electric potential due to the -2.6-µC charge at P? |-7.8E4 V (c) Find the total electric potential at P. -ЗЕ4 V (d) What is the work required to move a 3.4-µC charge from infinity to P? -1.02 Your response is off by a multiple of ten. J
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