The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a= 0.01, (b) a= 0.05, and (c) a= 0.10.P 0.1005O C. Fail to reject Ho because the P-value, 0.1005, is greater than a= 0.01.O D. Fail to reject Ho because the P-value, 0.1005, is less than a= 0.01.(b) Do you reject or fail to reject Ho at the 0.05 level of significance?O A. Fail to reject H, because the P-value, 0.1005, is less than a = 0.05.O B. Fail to reject Ho because the P-value, 0.1005, is greater than a= 0.05.C. Reject Ho because the P-value, 0.1005, is greater than a = 0.05.O D. Reject Ho because the P-value, 0.1005, is less than a = 0.05.(c) Do you reject or fail to reject H, at the 0.10 level of significance?O A. Reject Ho because the P-value, 0.1005, is less than a = 0.10.O B. Reject Ho because the P-value, 0.1005, is greater than a= 0.10.O C. Fail to reject Ho because the P-value, 0.1005, is less than a = 0.10.O D. Fail to reject H, because the P-value, 0.1005, is greater than a = 0.10.Click to select your answer. The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a=0.01, (b) a= 0.05, and (c) a= 0.10.P= 0.1005(a) Do you reject or fail to reject H, at the 0.01 level of significance?O A. Reject Ho because the P-value, 0.1005, is greater than a 0.01.O B. Reject H, because the P-value, 0.1005, is less than a = 0.01.O C. Fail to reject Ho because the P-value, 0.1005, is greater than a= 0.01.O D. Fail to reject H, because the P-value, 0.1005, is less than a = 0.01.(b) Do you reject or fail to reject Ho at the 0.05 level of significance?O A. Fail to reject H, because the P-value, 0.1005, is less than a = 0.05.O B. Fail to reject Ho because the P-value, 0.1005, is greater than a= 0.05.O C. Reject H, because the P-value, 0.1005, is greater than a= 0.05.O D. Reject Ho because the P-value, 0.1005, is less than a= 0.05.(c) Do you reject or fail to reject H, at the 0.10 level of significance?O A. Reject Ho because the P-value, 0.1005, is less than a= 0.10.Click to select your answer.@ ^ @II

Given information p-value = 0.1005

The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a= 0.01, (b) a = 0.05, and (c) a= 0.10 P=0.1005 O C. Fail to reject Ho because the P-value, 0.1005, is greater than a= 0.01. O D. Fail to reject Ho because the P-value, 0.1005, is less than a= 0.01. (b) Do you reject or fail to reject Ho at the 0.05 level of significance? O A. Fail to reject H, because the P-value, 0.1005, is less than a= 0.05. O B. Fail to reject Ho because the P-value, 0.1005 , is greater than a= 0.05 OC. Reject H, because the P-value, 0.1005, is greater than a= 0.05 O D. Reject Ho because the P-value, 0.1005, is less than a = 0.05. (c) Do you reject or fail to reject Ho at the 0.10 level of significance? O A. Reject Ho because the P-value, 0.1005, is less than a=0.10. O B. Reject Ho because the P-value, 0.1005, is greater than a = 0.10. O C. Fail to reject Ho because the P-value, 0.1005, is less than a = 0.10. O D. Fail to reject H, because the P-value, 0.1005, is greater than a=0.10. ali to relect your answer.

The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a= 0.01, (b) a = 0.05, and (c) a= 0.10 P=0.1005 O C. Fail to reject Ho because the P-value, 0.1005, is greater than a= 0.01. O D. Fail to reject Ho because the P-value, 0.1005, is less than a= 0.01. (b) Do you reject or fail to reject Ho at the 0.05 level of significance? O A. Fail to reject H, because the P-value, 0.1005, is less than a= 0.05. O B. Fail to reject Ho because the P-value, 0.1005 , is greater than a= 0.05 OC. Reject H, because the P-value, 0.1005, is greater than a= 0.05 O D. Reject Ho because the P-value, 0.1005, is less than a = 0.05. (c) Do you reject or fail to reject Ho at the 0.10 level of significance? O A. Reject Ho because the P-value, 0.1005, is less than a=0.10. O B. Reject Ho because the P-value, 0.1005, is greater than a = 0.10. O C. Fail to reject Ho because the P-value, 0.1005, is less than a = 0.10. O D. Fail to reject H, because the P-value, 0.1005, is greater than a=0.10. ali to relect your answer.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Test the claim that the mean GPA of night students is larger than 2.3 at the 0.10 significance level. The null and alternative hypothesis would be: Ho:u = 2.3 Ho:µ 0.575 Ho:p H1:µ + 2.3 H: µ > 2.3 H1:p 0.575 / 0.575 Ho:u > 2.3 Ho:p < 0.575 o The test is: left-tailed right-tailed two-tailed Based on a sample of 80 people, the sample mean GPA was 2.31 with a standard deviation of 0.06 The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis Question Help: DVideo OMessage instructor D Post to forum Cuhmit Oauntion P Type here to search %3 HEWLETT-PACKARD 米 IOI fo 144 A 2# 2$ 4 % & 3. 6. 7. R Y. D
Test the claim that the mean GPA of night students is smaller than 2.2 at the 0.005 significance level. The null and alternative hypothesis would be: Ho: u 0.55 Ho:p 2.2 o H1:µ > 2.2 H1:p 0.55 H1:p # 0.55 H1: µ 7 2.2 H1: p < 2.2 The test is: two-tailed right-tailed left-tailed o Based on a sample of 65 people, the sample mean GPA was 2.18 with a standard deviation of 0.06 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Rased on thic we P Type here to search HEWLETT - PAC ARD 12 esc 14 * 144 @ #3 $ % 1 3. 4 & 8. tab Q W T. Y. lock D F G C V.
Test the claim that the mean GPA of night students is smaller than 2.1 at the 0.025 significance level. The null and alternative hypothesis would be: Но: р > 0.525 Но: д 2.1 Но:р H:р 2.1 Н:n + 2.1 Hi:р > 0.525 Н: д < 2.1 Нј:р# 0.525 0.525 The test is: two-tailed left-tailed right-tailed Based on a sample of 70 people, the sample mean GPA was 2.07 with a standard deviation of 0.02 The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis O Fail to reject the null hypothesis
The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) α = 0.01, (b) α = 0.05, and (c) α = 0.10. P = 0.0176 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? A. Reject Ho because the P-value, 0.0176, is less than α = 0.01. B. Reject Ho because the P-value, 0.0176, is greater than α = 0.01. C. Fail to reject Ho because the P-value, 0.0176, is greater than α = 0.01. D. Fail to reject Ho because the P-value, 0.0176, is less than α = 0.01. (b) Do you reject or fail to reject Ho at the 0.05 level of significance? A. Fail to reject Ho because the P-value, 0.0176, is less than α = 0.05. B. Reject Ho because the P-value, 0.0176, is greater than α = 0.05. C. Reject Ho because the P-value, 0.0176, is less than α = 0.05. D. Fail to reject Ho because the P-value, 0.0176, is greater than α = 0.05. (c) Do you reject or fail to reject Ho at the 0.10 level of significance? A. Fail to reject Ho because the…
Test the claim that the mean GPA of night students is smaller than 2.5 at the 0.10 significance level. The null and alternative hypothesis would be: Но:р — 0.625 Но:р 0.625 Но:> 2.5 Но: д %3 2.5 Но: н 0.625 Н:р 2.5 The test is: right-tailed two-tailed left-tailed Based on a sample of 55 people, the sample mean GPA was 2.47 with a standard deviation of 0.03 The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is larger than the mean GPA of day students at the 0.005 significance level. The null and alternative hypothesis would be: Họ: PN 2 pp Họ:N 2 D Ho: PN PD H1 : UN + UD Hị:PN + PD H1: N > uD The test is: right-tailed two-tailed left-tailed The sample consisted of 30 night students, with a sample mean GPA of 2.18 and a standard deviation of 0.07, and 30 day students, with a sample mean GPA of 2.14 and a standard deviation of 0.08. The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level. The null and alternative hypothesis would be: Ho: HM = HF H,:PM = PF Ho: HM = PF Ho:HM = Pr Ho:PM = Pr Ho:PM PF H1: HM PF H1:HM > HF H1:HM # HF H1:PM + PF H1:PM < Pf The test is: right-tailed two-tailed left-tailed Based on a sample of 40 men, 40% owned cats Based on a sample of 40 women, 65% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 4 decimals) Based on this we: O Reject the null hypothesis OFail to reject the null hypothesis Check Answer
Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.01 significance level. The null and alternative hypothesis would be: PD Ho: PN PNPD H₁: PN PD The test is: right-tailed two-tailed O Ho: N D Ho: PN PD ≤ H₁N > HD O The test statistic is: The p-value is: ≥ Ho: N = HD Ho: PNPD Ho: UN D H₁: PN > PD H₁: UND H₁: PN < PD H₁: UN < HD O The sample consisted of 75 night students, with a sample mean GPA of 2.89 and a standard deviation of 0.08, and 75 day students, with a sample mean GPA of 2.9 and a standard deviation of 0.07. (to 2 decimals) Based on this we: left-tailed O O Reject the null hypothesis O Fail to reject the null hypothesis (to 2 decimals)
Test the claim that the mean GPA of night students is larger than 3.5 at the .005 significance level. The null and alternative hypothesis would be: Но: р — 0.875 Н,: р — 0.875 Но: р — 3.5 Но: р — 3.5 Но:р — 0.875 Hо: д — 3.5 Hа:р> 0.875 Н,:р40.875 H,:и # 3.5 Н;:и 3.5 The test is: two-tailed right-tailed left-tailed Based on a sample of 25 people, the sample mean GPA was 3.55 with a standard deviation of 0.04 The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: Ho: M = μF Ho: PM = PF H₁ μM μF H₁:PM > PF The test is: left-tailed right-tailed two-tailed Based on a sample of 60 men, 30% owned cats Based on a sample of 40 women, 45% owned cats The test statistic is: Ho: PM = PF H₁: PM μF (to 2 decimals) (to 2 decimals) Ho: PM = PF Ho: M = μF H₁:PM ‡ PF H₁: μM < MF
A medical equipment manufacturer believes that the proportion of faulty blood pressure monitors is greater than 0.11, the proportion stated by the supplier. We perform a hypothesis test at a significance level of 0.05 with the null and alternative hypothesis as follows: Ho: p = 0.11 and Ha: p < 0.11. A researcher inspects 150 items and finds 25 faulty ones. She gives a p-value of 0.01 in her analysis. Which of the following definitions is the correct interpretation of the p-value? O The probability of getting 25 or more faulty blood pressure monitors out of 150 if the true faulty rate is 0.11. The value that the z-statistic must be less than in order to reject the null hypothesis. The probability of rejecting a true null hypothesis. O The probability that the true rate of faulty items is 0.01.
K Use the IQ scores for the accompanying sample of individuals with low lead exposure to test the claim that they are from a population with a median IQ score of 100. Use a 0.01 significance level. Click the icon to view the data on IQ scores. F2 Find the null and alternative hypotheses. OA. Ho: Median = 100 H₁: Median #100 OC. Ho: Median = 100 H₁: Median 100 Find the test statistic. z=(Round to two decimal places as needed.) Find the P-value. F3 F4 F5 F6 W F7 DELL F8 Ō GET OB. Ho: Median # 100 H₁: Median = 100 OD. Ho: Median 100 H₁: Median = 100 F9 O F10 F11 :: F12 PrtScr 60 Submit quiz Insert Submit quiz 11:45 AM 4/9/2023 Delete