The ozonization of pentene in carbon tetrachloride solution at 25 °C C3H10 + O3C3H1003 is first order in C3H10 and first order in 03. Complete the rate law for this reaction in the box below. Use the form k[A]"[B]".. , where '1' is understood for m, n .. (don't enter 1) and concentrations taken to the zero power do not appear. Rate = k[C3H1,][O,] In an experiment to determine the rate law, the rate constant was determined to be 1.24x105 M's1. Using this value for the rate constant, the rate of the reaction when [C3H10] = 3.41×10² M and [O3] = 2.52x10-2 M would be 9.16x10^4 Ms-!.
The ozonization of pentene in carbon tetrachloride solution at 25 °C C3H10 + O3C3H1003 is first order in C3H10 and first order in 03. Complete the rate law for this reaction in the box below. Use the form k[A]"[B]".. , where '1' is understood for m, n .. (don't enter 1) and concentrations taken to the zero power do not appear. Rate = k[C3H1,][O,] In an experiment to determine the rate law, the rate constant was determined to be 1.24x105 M's1. Using this value for the rate constant, the rate of the reaction when [C3H10] = 3.41×10² M and [O3] = 2.52x10-2 M would be 9.16x10^4 Ms-!.
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**The Ozonization of Pentene in Carbon Tetrachloride Solution at 25 °C**
The chemical reaction:
\[ \text{C}_5\text{H}_{10} + \text{O}_3 \rightarrow \text{C}_5\text{H}_{10}\text{O}_3 \]
is first order in \(\text{C}_5\text{H}_{10}\) and first order in \(\text{O}_3\).
**Complete the rate law for this reaction in the box below.**
Use the form \( k[\text{A}]^m[\text{B}]^n \ldots \), where "1" is understood for \( m, n \ldots \) (do not enter 1) and concentrations taken to the zero power do not appear.
**Rate Law:**
\[ \text{Rate} = k[\text{C}_5\text{H}_{10}][\text{O}_3] \]
**Additional Experimentation:**
In an experiment to determine the rate law, the rate constant was determined to be \( 1.24 \times 10^{5} \, \text{M}^{-1}\text{s}^{-1} \). Using this value for the rate constant, the rate of the reaction when \([\text{C}_5\text{H}_{10}] = 3.41 \times 10^{-2} \, \text{M}\) and \([\text{O}_3] = 2.52 \times 10^{-2} \, \text{M}\) would be \( 9.16 \times 10^4 \, \text{M/s} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4eca0ea-f525-4d8f-9259-04e892974916%2F72409d2a-78b7-4e03-b0a0-ef951242e418%2Fo1w5muii_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**The Ozonization of Pentene in Carbon Tetrachloride Solution at 25 °C**
The chemical reaction:
\[ \text{C}_5\text{H}_{10} + \text{O}_3 \rightarrow \text{C}_5\text{H}_{10}\text{O}_3 \]
is first order in \(\text{C}_5\text{H}_{10}\) and first order in \(\text{O}_3\).
**Complete the rate law for this reaction in the box below.**
Use the form \( k[\text{A}]^m[\text{B}]^n \ldots \), where "1" is understood for \( m, n \ldots \) (do not enter 1) and concentrations taken to the zero power do not appear.
**Rate Law:**
\[ \text{Rate} = k[\text{C}_5\text{H}_{10}][\text{O}_3] \]
**Additional Experimentation:**
In an experiment to determine the rate law, the rate constant was determined to be \( 1.24 \times 10^{5} \, \text{M}^{-1}\text{s}^{-1} \). Using this value for the rate constant, the rate of the reaction when \([\text{C}_5\text{H}_{10}] = 3.41 \times 10^{-2} \, \text{M}\) and \([\text{O}_3] = 2.52 \times 10^{-2} \, \text{M}\) would be \( 9.16 \times 10^4 \, \text{M/s} \).
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