The oxidation of nitrogen monoxide by oxygen at 25 °C 2 NO + 022 NO2 is second order in NO and first order in O2. Complete the rate law for this reaction in the box below. Use the form k[A]"B]".. , where '1' is understood for m, n . (don't enter 1) and concentrations taken to the zero power do not appear. Rate = In an experiment to determine the rate law, the rate of the reaction was determined to be 6.91×10o-4 Ms1 when [NO] = 5.26x103 M and [02] = 2.53x103 M. From this experiment, the rate constant is

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**The Oxidation of Nitrogen Monoxide by Oxygen at 25°C**

**Reaction:**
\[ 2 \text{NO} + \text{O}_2 \rightarrow 2 \text{NO}_2 \]

This reaction is second order in \(\text{NO}\) and first order in \(\text{O}_2\).

**Rate Law Completion:**
To write the rate law for this reaction, use the form \( k[\text{A}]^m[\text{B}]^n \), where '1' is understood for \( m, n \) (don't enter 1), and concentrations taken to the zero power do not appear.

**Rate =** 

\[ k[\text{NO}]^2[\text{O}_2] \]

**Experimental Data:**  
In an experiment to determine the rate law, the rate of the reaction was determined to be \( 6.91 \times 10^{-4} \, \text{M s}^{-1} \) when \([\text{NO}] = 5.26 \times 10^{-3} \, \text{M} \) and \([\text{O}_2] = 2.53 \times 10^{-3} \, \text{M} \). From this experiment, the rate constant is \( \boxed{k} \, \text{M}^{-2}\text{s}^{-1} \).
Transcribed Image Text:**The Oxidation of Nitrogen Monoxide by Oxygen at 25°C** **Reaction:** \[ 2 \text{NO} + \text{O}_2 \rightarrow 2 \text{NO}_2 \] This reaction is second order in \(\text{NO}\) and first order in \(\text{O}_2\). **Rate Law Completion:** To write the rate law for this reaction, use the form \( k[\text{A}]^m[\text{B}]^n \), where '1' is understood for \( m, n \) (don't enter 1), and concentrations taken to the zero power do not appear. **Rate =** \[ k[\text{NO}]^2[\text{O}_2] \] **Experimental Data:** In an experiment to determine the rate law, the rate of the reaction was determined to be \( 6.91 \times 10^{-4} \, \text{M s}^{-1} \) when \([\text{NO}] = 5.26 \times 10^{-3} \, \text{M} \) and \([\text{O}_2] = 2.53 \times 10^{-3} \, \text{M} \). From this experiment, the rate constant is \( \boxed{k} \, \text{M}^{-2}\text{s}^{-1} \).
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