The reaction of nitrogen dioxide with carbon monoxide NO, + CONO0 + CO2 is second order in NO, and zero order in CO. Complete the rate law for this reaction in the box below, Use the form k[A]™[B]"... , where 'l' is understood for m, n . (don't enter 1) and concentrations taken to the zero power do not appear. Rate = In an experiment to determine the rate law, the rate constant was determined to be 0.780 M's. Using this value for the rate constant, the rate of the reaction when [NO,] = 0.460 M and [CO] = 0.372 M would be Ms!.

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**The Reaction of Nitrogen Dioxide with Carbon Monoxide**

**Reaction:**  
\[ \text{NO}_2 + \text{CO} \rightarrow \text{NO} + \text{CO}_2 \]

- The reaction is second order in \(\text{NO}_2\) and zero order in \(\text{CO}\).

**Rate Law:**  
Complete the rate law for this reaction in the box below. Use the form \( k[\text{A}]^m[\text{B}]^n \ldots \), where '1' is understood for \( m, n \ldots \) (do not enter 1) and concentrations taken to the zero power do not appear.

**Rate =**  
\[ k[\text{NO}_2]^2 \]

**Experimental Determination:**  
In an experiment to determine the rate law, the rate constant was determined to be \( 0.780 \, \text{M}^{-1}\text{s}^{-1} \).  

Using this value for the rate constant, the rate of the reaction when \([\text{NO}_2] = 0.400 \, \text{M}\) and \([\text{CO}] = 0.372 \, \text{M}\) would be:

**Rate =**  
\(k[\text{NO}_2]^2 = 0.780 \times (0.400)^2 = 0.1248 \, \text{Ms}^{-1}\).

(Note: Since CO is zero order, its concentration does not affect the rate and does not appear in the rate law.)
Transcribed Image Text:**The Reaction of Nitrogen Dioxide with Carbon Monoxide** **Reaction:** \[ \text{NO}_2 + \text{CO} \rightarrow \text{NO} + \text{CO}_2 \] - The reaction is second order in \(\text{NO}_2\) and zero order in \(\text{CO}\). **Rate Law:** Complete the rate law for this reaction in the box below. Use the form \( k[\text{A}]^m[\text{B}]^n \ldots \), where '1' is understood for \( m, n \ldots \) (do not enter 1) and concentrations taken to the zero power do not appear. **Rate =** \[ k[\text{NO}_2]^2 \] **Experimental Determination:** In an experiment to determine the rate law, the rate constant was determined to be \( 0.780 \, \text{M}^{-1}\text{s}^{-1} \). Using this value for the rate constant, the rate of the reaction when \([\text{NO}_2] = 0.400 \, \text{M}\) and \([\text{CO}] = 0.372 \, \text{M}\) would be: **Rate =** \(k[\text{NO}_2]^2 = 0.780 \times (0.400)^2 = 0.1248 \, \text{Ms}^{-1}\). (Note: Since CO is zero order, its concentration does not affect the rate and does not appear in the rate law.)
**The reaction for the formation of phosgene from carbon monoxide and chlorine**

\[ \text{CO} + \text{Cl}_2 \longrightarrow \text{COCl}_2 \]

is first order in CO and second order overall.

**Complete the rate law for this reaction in the box below.**

Use the form k[A]^m[B]^n..., where '1' is understood for m, n... *(don't enter 1)* and concentrations taken to the zero power do not appear.

**Rate =** [Text box]
Transcribed Image Text:**The reaction for the formation of phosgene from carbon monoxide and chlorine** \[ \text{CO} + \text{Cl}_2 \longrightarrow \text{COCl}_2 \] is first order in CO and second order overall. **Complete the rate law for this reaction in the box below.** Use the form k[A]^m[B]^n..., where '1' is understood for m, n... *(don't enter 1)* and concentrations taken to the zero power do not appear. **Rate =** [Text box]
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