KThe numbers of courses taught per semester by a random sample of university professors are shown in the histogram. Make a frequency distributionfor the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set.Make a frequency distribution for the data.X1234fThe sample mean is x =(Round to one decimal place as needed.)The sample standard deviation is s = 0(Round to one decimal place as needed.)MacBook AirNumber of professors25-20-15-10-5-518221312Number of courses taught per semesterTime Remaining: 00:52:39Question ViewerNext

Given: The random variable X is the number of courses taught per semester by the university…

Answered: The numbers of courses taught per…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you conclude? Standard deviation CV = • 100% Mean E Click the icon to view the data sets. Data Table ..... CVneights = 71.2% (Round to the nearest tenth as needed.) Heights Weights 68 181 77 169 72 167 72 207 71 177 70 175 78 185 69 186 67 221 70 216 67 209 73 206
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.1 miles per hour. 58 - 61 Speed (miles per hour) Frequency 42 - 45 29 46 - 49 14 50 - 53 54 - 57 3 ..... The mean of the frequency distribution is miles per hour. (Round to the nearest tenth as needed.) Which of the following best discribes the relationship between the computed mean and the actual mean? O A. The computed mean is close to the actual mean because the difference between the means is more than 5%. O B. The computed mean is not close to the actual mean because the difference between the means is more than 5%. O C. The computed mean is close to the actual mean because the difference between the means is less than 5%. O D. The computed mean is not close to the actual mean because the difference between the means is less than 5%.
The numbers of courses taught per semester by a random sample of university professors are shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. 25- 24 20- 17 16 15 10- 5- Number of courses taught per semester f 1 2 16 24 4 17 The sample mean is x = 2.9 (Round to one decimal place as needed.) The sample standard deviation is s = (Round to one decimal place as needed.) Number of professors
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 57.4 degrees. The mean of the frequency distribution is (Round to the nearest tenth as needed.)
Use the dataset below to fill in the blanks. The space between the data and the blanks isprovided so that you can show each data value's deviation and each data value's deviation squared.Sixteen families were selected at random and the number of children in each was recorded 0 0 0 1 1 2 2 2 2 2 3 3 4 6 8 12
Aу 30+ 25- 20- 15- 10- 5- 2 14 23 2 0+ 48.5 70.5 92.5 114.5 136.5 158.5 x
The distribution of the number of hours that a random sample of people spend doing chores per week is shown in the pie chart. Use 32 as the midpoint for "30+ hours." Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. W Click the icon to view the pie chart. First construct the frequency distribution. Weekly study hours Class Frequency, f 0-4 I 0-4 hours (4 people) 5-9 1 5-9 hours (12 people) O 10-14 hours (23 people) O 15-19 hours (21 people) O 20-24 hours (16 people) O 25-29 hours (14 people) O 30+ hours (5 people) 10-14 15-19 20-24 25-29 30+ Print Done OOOOD OD
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Use the following set of values for #10 - 13. Round answers to nearest hundredth, if necessary. .3, .6, 9, 1.3, .4, .6, 1.2, 1.4, 1.1, .2, .2 10. Find the mean, median, and mode(s) 11. Find the range 12. Find the interquartile range 13. Find the standard deviation
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.5 degrees. Low Temperature (o F) 40 - 44 45 - 49 50 - 54 55 - 59 60 – 64 D Frequency 2 9. ... The mean of the frequency distribution is degrees. (Round to the nearest tenth as needed.) Which of the following best describes the relationship between the computed mean and the actual mean? O A. The computed mean is close to the actual mean because the difference between the means is more than 5% of the actual mean. B. The computed mean is not close to the actual mean because the difference between the means is less than 5% of the actual mean. C. The computed mean is not close to the actual mean because the difference between the means is more than 5% of the actual mean. D. The computed mean is close to the actual mean because the difference between the means is less than 5% of the actual mean.
The numbers of courses taught per semester by a random sample of university professors are shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Make a frequency distribution for the data. X 1 3 f Number of professors 25- 20- 15- 10- 4 20 23 15 1 2 3 4 Number of courses taught per semester

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