The null and alternative hypothesis would be: Ho: p < 0.9 Ho:μ < 0.9 Ho:μ 2 0.9 H :μ H₁:p> 0.9 H₁: >0.9 H₁: < 0.9 H₁: The test is: two-tailed right-tailed left-tailed O The test statistic is: The p-value is: Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis 0.9 Ho:p= 0.9 Ho:p> 0.9 0.9 H₁:p 0.9 H₁: p < 0.9 (to 3 decimals) (to 4 decimals)
The null and alternative hypothesis would be: Ho: p < 0.9 Ho:μ < 0.9 Ho:μ 2 0.9 H :μ H₁:p> 0.9 H₁: >0.9 H₁: < 0.9 H₁: The test is: two-tailed right-tailed left-tailed O The test statistic is: The p-value is: Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis 0.9 Ho:p= 0.9 Ho:p> 0.9 0.9 H₁:p 0.9 H₁: p < 0.9 (to 3 decimals) (to 4 decimals)
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
Problem 11PPS
Related questions
Question
100%
Question 17: A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 100 people, 81% of them said they are confident of meeting their goals.
Test the claim that the proportion of people who are confident is smaller than 90% at the 0.05 significance level.
The null and alternative hypothesis would be:
H0:p≤0.9H0:p≤0.9
H1:p>0.9H1:p>0.9
H1:p>0.9H1:p>0.9
H0:μ≤0.9H0:μ≤0.9
H1:μ>0.9H1:μ>0.9
H1:μ>0.9H1:μ>0.9
H0:μ≥0.9H0:μ≥0.9
H1:μ<0.9H1:μ<0.9
H1:μ<0.9H1:μ<0.9
H0:μ=0.9H0:μ=0.9
H1:μ≠0.9H1:μ≠0.9
H1:μ≠0.9H1:μ≠0.9
H0:p=0.9H0:p=0.9
H1:p≠0.9H1:p≠0.9
H1:p≠0.9H1:p≠0.9
H0:p≥0.9H0:p≥0.9
H1:p<0.9H1:p<0.9
H1:p<0.9H1:p<0.9
The test is:
two-tailed
right-tailed
left-tailed
The test statistic is: (to 3 decimals)
The p-value is: (to 4 decimals)
Based on this we:
- Fail to reject the null hypothesis
- Reject the null hypothesis
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