A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these social outreach programs should be located based on the percentage of residents living below the poverty line in each region of the city. He takes a simple random sample of 129 people living in Gastown and finds that 25 have an annual income that is below the poverty line.   Suppose that the government official wants to re-estimate the population proportion and wishes for his 95% confidence interval to have a margin of error no larger than 0.05. How large a sample should he take to achieve this? Please carry answers to at least six decimal places in intermediate steps.   Sample size = Answer

Q: A recent study of high school students shows the percentage of females and males who have at LEAST…

A: The (1-α)% confidence interval for the difference in population proportions p1-p2 is given by;…

Q: Dr. Kijowski is concerned about student phone use, so she collects information on the number of text…

A: Given that Dr. Kijowski is concerned about student phone use, so she collects information on the…

Q: A random sample of nine students took 18, 19, 13, 24, 22, 21, 22, 17, and 25 minutes to complete the…

A:

Q: The figure to the right shows the results of a survoy in which 1013 adults from Country A, 1001…

A: It was found that out of the 1013 adults from country A, 33% of the adults say national identity is…

Q: Additional Problem: In a Gallup Social Series Poll on Crime conducted last October with 691 female…

A: Given : Claim : fewer than 50% of female adults believed that crime increased in the area in which…

Q: In studying his campaign plans, Mr. Singleton wishes to estimate the difference between younger…

A: sample size(n1)=769x1=497sample size(n2)=703x2=390confidence level=90%

Q: Kim wants to determine a 80 percent confidence interval for the true proportion of high school…

A: Given: Margin of error, E=0.04 Confidence level=80%

Q: Dylan wants to determine a 95% confidence interval for the true proportion of high school students…

A:

Q: 88% of California adults (444 out of 506 surveyed) feel that education is one of the top issues…

A: The value of z at a 90% confidence level is 1.645, which can be obtained by using the standard…

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: As Senior Class President, one of your lifelong duties is overseeing the planning of your high…

A:

Q: Refer to the following scenario. Ah epidemiologist is worned about the prevalence of the flu in…

A: Givenx=39n=334p^=xn=39334=0.116766Margin of error(E)=0.05Confidence…

Q: Does a new diet plan help people lose weight? Twenty people were weighed before starting a 3-month…

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: A principal of a large high school wants to estimate the true proportion of high school students who…

A: Given information- Sample size, n = 50 For a random sample of 50 students, the 95% confidence…

Q: A large company would like to assess the impact of using a professional trainer to conduct a…

A: We hvae to find corrcet option..

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: The FBI wants to determine the effectiveness of their 1010 Most Wanted list. To do so, they need to…

A:

Q: A recent survey of 54,000 randomly selected adults studied the religious affiliations of Americans.…

A: From the provided information, Sample size (n) = 645 From which 116 said they claimed no religious…

Q: The analyst decides to test this assumption by collecting a random sample of 100 New Yorkers and…

A: The sample proportion is, p^=xn=65100=0.65 Computation of critical value:…

Q: Construct a 99% confidence interval to assess whether this represents evidence that parents'…

A:

Q: In a certain school, 30% of the student body is taking a biology class. Of the biology students, 35%…

A: Given; P(biology class)=30%=0.3 P(other science class)=1-0.3=0.7 P(B in the class/biology…

Q: Part a and b

A:

Q: The figure to the right shows the results of a survey in which 999 adults from Country​ A, 1006…

A: Hey, since there are multiple subparts posted, we will answer the first three subparts. If you want…

Q: Suppose that a health expert has claimed that 28% of college students smoke cigarettes. To…

A: Given 95% confidence interval for the percentage of college students who smoke is 19% to 24%. Given…

Q: You are going to construct a 99% confidence interval for the proportion of hip replacement…

A:

Q: The police department wants to reduce the margin of error for their 95% confidence interval. If they…

A: Here Given  The police department wants to reduce the margin of error for their 95% confidence…

Q: Cora wants to determine a 90% confidence interval for the true proportion of high school students in…

A: Confidence level=90%Margin of error(E)=0.02Assuming that we have no prior estimate of the proportion…

Q: wenty years ago, a very famous psychologist specializing in marriage counseling authored a book…

A: Solution: Given information n= 275 Sample size of couples who bought book. X= 217  stayed together…

Q: If 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25 create and…

A: Given,   Sample size = 550 Sample proportion = 0.64   Critical value: Using z-table, the z-critical…

Q: A survey of credit card holders revealed that Americans carried an average credit card balance of…

A: M1=$3900M2=$3300n1=400n2=450σ1=$880σ2=$810

Q: An epidemiologist is worried about the prevalence of the flu in East Vancouver and the potential…

A:

Q: A certain coffee packing company has three packing lines with the following production volumes of…

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Q: A soft drink company surveys 500 shoppers and finds that 61% of shoppers prefer diet soda to regular…

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Q: CNN is conducting a poll, and wants to produce a 90% confidence interval for the proportion of all…

A: a) Given that 602 randomly selected Ne Yorkers surveyed, 394 were in favor of the initiative.…

Q: Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.