A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 600 people, 570 of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 90% at the 0.01 significance level. The null and alternative hypothesis would be: Но:р 3 0.9 Но:д — 0.9 Но:р — 0.9 Но:р%3D 0.9 Но:д — 0.9 Но:р — 0.9 H:р < 0.9 Н:р < 0.9 H:p> 0.9 Hj:p # 0.9 Hi:д # 0.9 Hi:р> 0.9 The test is: two-tailed right-tailed left-tailed The test statistic is: (to 3 decimals) The p-value is: (to 4 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis

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Question 15
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A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their
investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample
of 600 people, 570 of them said they are confident of meeting their goals.
Test the claim that the proportion of people who are confident is larger than 90% at the 0.01 significance
level.
The null and alternative hypothesis would be:
Ho:P
0.9 Но: и 3 0.9 Но:р
—D 0.9 Но:р
H1:p < 0.9 H1:µ < 0.9 H1: µ > 0.9 H1:p 7 0.9 H1: µ + 0.9 H1:p > 0.9
0.9 Но:и 3 0.9 Но:р — 0.9
The test is:
two-tailed right-tailed left-tailed
The test statistic is:
(to 3 decimals)
The p-value is:
(to 4 decimals)
Based on this we:
Fail to reject the null hypothesis
Reject the null hypothesis
Transcribed Image Text:Question 15 > A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 600 people, 570 of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 90% at the 0.01 significance level. The null and alternative hypothesis would be: Ho:P 0.9 Но: и 3 0.9 Но:р —D 0.9 Но:р H1:p < 0.9 H1:µ < 0.9 H1: µ > 0.9 H1:p 7 0.9 H1: µ + 0.9 H1:p > 0.9 0.9 Но:и 3 0.9 Но:р — 0.9 The test is: two-tailed right-tailed left-tailed The test statistic is: (to 3 decimals) The p-value is: (to 4 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
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