The null and alternate hypotheses are:Ho Hy H2H₁ H₁ H₂A random sample of 11 observations from one population revealed a sample mean of 23 and a sample standard deviation of 1.1. Arandom sample of 4 observations from another population revealed a sample mean of 24 and a sample standard deviation of 1.3.The population standard deviations are unknown but assumed to be equal. At the 0.05 significance level, is there a differencebetween the population means?Required:a. State the decision rule. (Negative amounts should be indicated by a minus sign. Round your answer to 3 decimal places.)Answer is complete but not entirely correct.-1.761 or1.761The decision rule is to reject Hob. Compute the pooled estimate of the population variance. (Round your answer to 3 decimal places.)Pooled estimate of the population variance c. Compute the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)Test statisticd. State your decision about the null hypothesis.Do not reject HoReject Hoe. The p-value isbetween 0.2 and 0.1.less than 0.001.between 0.02 and 0.05.between 0.001 and 0.01.between 0.05 and 01.

The given hypothesis is H0:μ1=μ2 Vs H1:μ1≠μ2. The population standard deviations are unknown but…

Answered: The null and alternate hypotheses are:…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 89 tourists in Chattanooga (C) showed that they spent an average of $2860 (in a week) with a standard deviation of $126; and a sample of 64 tourists in Orlando (0) showed that they spent an average of $2935 (in a week) with a standard deviation of $138. We are interested in determining if there is any significant difference between the average expenditures of all the tourists who visited the two cities. Test the following hypotheses: Ho: Hc = Ho a. Calculate the value of the test statistic. (Round to two decimal places) b. What is the p-value? (Round to four decimal places) c. At a 1% significance level, the decision is to
A large international company with over 1.5 million employees wants to estimate how many of their employees have a cholesterol level that is higher than the recommended level. The company collects data from a random sample of employees and creates a 95% confidence interval for the population mean cholesterol level for all company employees. The upper bound of a 95% confidence interval for the population mean cholesterol level was 261.48, and the width of the same 95% confidence interval was 10.44. In this confidence interval, what is the sample mean (x bar) cholesterol level? Provide your answer as a number rounded to two decimal places
The average expenditure per student (based on average daily attendance) for a certain school year was $10,337 with a population standard deviation of $1560. A survey for the next school year of 150 randomly selected students resulted in a sample mean of $10, 798. Find the Z statistics? Should the null hypothesis be rejected at alpha = .05 level of significance?
When 50 people used a certain diet for one year, their weight losses had a standard deviation of 5.4lb. Use a 0.05 significance level to test the claim that the amounts of weight loss have a standard deviation equal to 6.0lb, which appears to be the standard deviation for the amounts of weight loss with a different diet. Assume that a simple random sample is selected from a normally distributed population. What are the correct hypotheses for this test? H0: H1: Calculate the value of the test statistic. (Round to two decimal places as needed.) Use technology to determine the P-value for the test statistic. The P-value is (Round to three decimal places as needed.) What is the conclusion at the 0.05 level of significance? Since the P-value is ......(greater than/less than/equal to)the level of significance,......(do not reject/ reject) the null hypothesis. There ....(is/ is not) sufficient evidence to conclude that the sample is from a population with a…
Scores on a certain "IQ" test for 18-25 year olds are normally distributed. A researcher believes that the average IQ score for students at a certain NJ college is less than 110 points, and so wants to test this hypothesis. The researcher obtain a SRS of 45 student IQ scores from school records and found the mean of the 45 results was 108 with a sample standard deviation of 21. The level of significance (alpha) used for this problem is 0.05. What is the appropriate test statistic (Student must complete by showing by formula using the ap- propriate values in that formula "showing work" and the final answer and appropriate label)? O T test score = (108-110)/(21/sqrt(45)) = -.639 T test score (108-110)/(21/sqrt(45)) = .639 %3D OT test score = (110-108)/(21/sqrt(45)) = .639 %3D T test score (108-110)/(45/sqrt(21)) =-.2037 %3D 素

Consider a dataset containing the heights of 38 females who said they prefer to sit in the front of the classroom yields a sample average of 62 inches and a sample standard deviation of 2.5 inches. Suppose that the average height for the general population of college females is 65 inches. An analyst wants to test the claim that the true average height of females who prefer to sit in the front of the classroom is lower than it is for the general population. In the hypothesis for the above claim (at significance level of 10%), the appropriate test, test statistic (name and value), and pvalue is the approximate Z-test with z-statistic = 62 and pvalue = 0. the approximate Z-test with z-statistic = 7.40 and pvalue not calculable because normality is not given. = 0. the approximate Z-test with z-statistic = -7.40 and pvalue = 0.
The average American consumes 89 liters of alcohol per year. Does the average college student consume less alcohol per year? A researcher surveyed 15 randomly selected college students and found that they averaged 87.3 liters of alcohol consumed per year with a standard deviation of 15 liters. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? Select an answer V Н: ? v Select an answer V c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... the null hypothesis. O The data suggest the population mean is not significantly less than 89 at a = 0.05, so there is statistically insignificant evidence to conclude that the population mean amount of alcohol consumed by college students…
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1. The strength of steel wire made by an existing process is normally distributed with a mean of 1550 and a standard deviation of 170. A batch of wire is made by a new process, and a random sample consisting of 25 measurements gives an average strength of 1316. Assume that the standard deviation does not change. Is there evidence at the 1% level of significance that the new process gives a larger mean strength than the old? To answer this question, the null hypothesis could be stated as A. μ= 1550 psi B. μ> 1550 psi C.µ + 1550 psi D. μ< 1550 psi
Read each situation and perform the appropriate test of hypothesis for the one sample mean z-test and t-test. 2. A manufacturer claims that their car batteries have a mean life expectancy of 6 years with a population standard deviation of 1.75 years. In order to test its own claim, a random sample of 35 batteries were tested and it was found out their mean life span is 5. 5 years. Is there evidence at the 0.01 level of significance that the batteries become exhausted in less than 6 years?
In a test of hypothesis, the null hypothesis is that the population mean is equal to 90 and the alternative hypothesis is that the population mean is not equal to 90. A sample of 16 elements selected from this population produced a mean of 86.75 and a standard deviation of 12.54. The significance level is 2%. a. –2.602 and 2.602 b. –2.583 and 2.583 c. –2.131 and 2.131 d. –1.341 and 1.341
The human resources department of a large investment bank announced that the number of people it interviews monthly has a mean of 115 with a standare deviation of 15.4. The management of the bank suspects that the standard deviation exceeds 15.4. Suppose that the management wants to take a small sample of months and carry out a hypothesis test to see if its suspicions have support. State the null hypothesis H, and the alternative hypothesis H, that is would use for this test. Ho: O H₁: 0 μ 5 OSO ローロ X X a > * 3 р S 20

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