Kurtis is a statistician who claims that the average salary of an employee in the city of Yarmouth is no more than $55,000per year. Gina, his colleague, believes this to be incorrect, so she randomly selects 61 employees who work in Yarmouth andrecord their annual salary. Gina calculates the sample mean income to be $56,500 per year with a sample standarddeviation of 3,750. Using the alternative hypothesis H1 : 55.0appropriate hypothesis test. Round the test statistic to two decimal places and the p-value to three decimal places.Right-Tailed T-TableprobabilityDegrees ofFreedom540.00040.00140.00240.00340.00440.00540.006456575859603.562 3.135 2.943 2.816 2.719 2.641 2.5763.558 3.132 2.941 2.814 2.7172.640 2.5743.554 3.130 2.939 2.8122.716 2.638 2.5723.550 3.127 2.937 2.810 2.714 2.636 2.5713.547 3.125 2.935 2.8082.712 2.635 2.5693.544 3.122 2.933 2.806 2.711 2.633 2.5683.540 3.120 2.931 2.805 2.709 2.632 2.567Provide your answer below, p-value -

State the appropriate hypothesis:Denote the population mean as μ.The investigator is interested to…

Answered: Kurtis is a statistician who claims…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Insurance Company A claims that its customers pay less for car insurance, on average than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 11 people who buy insurance from Company A, the mean cost is $⁢150 per month with a standard deviation of $⁢14. For 14 randomly selected customers of Company B, you find that they pay a mean of $⁢158 per month with a standard deviation of $⁢12. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places.
A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,738. Suppose that a random sample of 50 accounting graduates at a large university who received job offers resulted in a mean offer of $49,830 and a standard deviation of $3800. Do the sample data provide strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the national average of $48,738? Test the relevant hypotheses using ? = 0.05. (Use a statistical computer package to calculate the P-value. Round your test statistic to two decimal places and your P-value to three decimal places.) t = P-value =
A report states that the mean yearly salary offer for students graduating with mathematics and statistics degrees is $62,915. Suppose that a random sample of 50 mathematics and statistics graduates at a large university who received job offers resulted in a mean offer of $63,200 and a standard deviation of $3,700. Do the sample data provide strong support for the claim that the mean salary offer for mathematics and statistics graduates of this university is greater than the national average of $62,915? Test the relevant hypotheses using a = 0.05. USE SALT Find the test statistic and P-value. (Use technology to calculate the P-value. Round your test statistic to two decimal places and your P-value to four decimal places.) t = P-value = State your conclusion. O Reject Ho. We have convincing evidence that the mean salary offer for mathematics and statistics graduates of this university is greater than the national average of $62,915. Fail to reject H. We have convincing evidence that the…
According to the College Board, scores on the math section of the SAT Reasoning college entrance test for the class of 2010 had a mean of 516 and a standard deviation of 116. Assume that they are roughly normal.One of the quartiles of the scores from the math section of the SAT Reasoning test is 438. The other quartile is _______.
Which of the following is closest to the correct test statistic for this hypothesis test?
Justine is an analyst for a sleep study center. She believes that the average adult in a certain city spends more than 7.2 hours sleeping daily. To test this claim, she selects a random sample of 63 adults from the city. The following is the data from this study: The alternative hypothesis Ha:μ>7.2. The sample mean number of hours slept per night by the 63 adults is 7.52 hours. The sample standard deviation is 1.14 hours. The test statistic is calculated as 2.23. Using the information above and the portion of the t− table below, choose the correct p− value and interpretation for this hypothesis test. Values for right-tail areas under the t-distribution curve Probability 0.10 0.05 0.025 0.01 0.005 Degrees of Freedom 60 1.296 1.671 2.000 2.390 2.660 61 1.296 1.670 2.000 2.389 2.659 62 1.295 1.670 1.999 2.388 2.657 63 1.295 1.669 1.998 2.387 2.656 64 1.295 1.669 1.998 2.386 2.655 65 1.295 1.669 1.997 2.385 2.654 66 1.295 1.668 1.997 2.384 2.652…
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
Suppose we wish to study the average income of Cactus Club customers, so we plan to conduct a research project with a 95% confidence level. We need our range of error (E) to be no greater than $500. Based on our past experience, we estimate the sample standard deviation to be $5,000. What sample size do you need in order to conduct the research? Select one: a. 372 b. 784 c. 824 d. 385 e. 196
Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 12people who buy insurance from Company A, the mean cost is $153 per month with a standard deviation of $16. For 15 randomly selected customers of Company B, you find that they pay a mean of $160 per month with a standard deviation of $10. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. H0: μ1=μ2 Ha: μ1_____μ2 Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places Step 3 of…
In a particular year, registered nurses earned an average annual salary of $52,330. A survey was conducted with 48 nurses from a particular state to determine if the annual salary is higher than $52,330 for that state's nurses. The sample average was $61,599 with a sample standard deviation of $7,489. Conduct a hypothesis test at the 5% level.Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) State the distribution to use for the test. (Enter your answer in the form z or tdf where df is the degrees of freedom.) What is the test statistic? (Round your answer to two decimal places.) What is the p-value? (Round your answer to four decimal places.) Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence interval. (Round your answers to the…
A Two-Sample Hypothesis TestThe mean number of English courses taken in a two-year time period by male and female college students is believed to be about the same. An experiment is conducted and data are collected from 29 males and 16 females. The males took an average of three English courses with a standard deviation of 0.8. The females took an average of four English courses with a standard deviation of 1.0. Are the means statistically the same? (Assume a 5% level of significance.)Useful tools:Normal Distribution Calculatort-Distribution Calculator 1. Which of the following null and alternative hypotheses match this scenario? A---H0:Δμ=0H0:Δμ=0Ha:Δμ≠0Ha:Δμ≠0 B---H0:Δμ≠0H0:Δμ≠0Ha:Δμ=0Ha:Δμ=0 C---H0:Δμ=0H0:Δμ=0Ha:Δμ>0 2. Which type of test should be applied? A---The alternative hypothesis indicates a right-tailed test. B---The alternative hypothesis indicates a left-tailed test. C---The alternative hypothesis indicates a two-tailed test. 3. Which type of distribution should be…
Which outcome is expected if the null hypothesis is true for an analysis of variance? a. SSbetween should be about the same size as SStotal. b. SSbetween should be about the same size as SSwithin. c. MSbetween should be about the same size as MStotal. d. MSbetween should be about the same size as MSwithin.

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