Determine appropiate test statistic to use and test the hypothesis under 5% significance level. Show work please. The National High School Health Survey (NHSHS) indicates that about 50% of 12th graders consume lessthan 300g of vegetables at lunch, about 40% consume 300-600g, and only 10% of them consume morethan 600g. A high school conducted a survey of student diets and health information, and reported dataabout 12th graders' vegetable intake at lunch:Vegetable Intake in gram Total300g -600g278300gFrequency 150600g98 526

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Answered: The National High School Health Survey…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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I need test statistic, p-value, conclusion for hypothesis test, and "Does nausea to appear to be a problematic adverse reaction?"
The average retirement age in America is 64 years old. Do small business owners retire at a younger average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 63, 54, 69, 69, 53, 53, 71, 51, 61, 60, 69, 54 What can be concluded at the the a = 0.01 significance level What is the test statistic and the p value?
A survey conducted on a group of 250 people randomly recruited from among the retirees revealed that 115 people were willing to find a new job. It is known that the rate of those who previously wanted to work among retired people is 67%. Can it be claimed that the ratio of these two tendencies is different from each other for the 2% significance level? Test it, interpret the decision you made as a result of the test. While testing the hypothesis test, apply the 4 stages and show them separately.
Historically, the percentage of U.S. residents who support stricter gun control laws has been 55%. A recent Gallup Poll of 2500 people showed 1723 in favor of stricter gun control laws . Assume the poll was given to a random sample of people. QUESTION Test the claim that the proportion of those favoring stricter gun control has changed from 0.55. Perform a hypothesis test, using a significance level of 0.01. . What is the Z crit? +/- 1.96 +/- 1.645 +/- 2.58 +/- 2.326
The average retirement age in America is 66 years old. Do small business owners retire at an older average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 63, 74, 59, 64, 74, 60, 71, 67, 65, 70, 63 What can be concluded at the the � = 0.05 level of significance level of significance? For this study, we should use The null and alternative hypotheses would be: �0: �1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is � Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly older than 66 at � = 0.05, so there is sufficient evidence to conclude that the population mean retirement age for small business owners is older than 66. The data suggest…
I need help with this problem Conduct a hypothesis test about the mean cost per square foot at a chosen significance level. Reference an internet source for the current average (or median) cost per square foot of homes in Orange County. Discuss/explain your choice of significance level for your hypothesis test in #1 as it relates to the power of a test and Type I/II errors.
Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use a significance level of 0.05 to test the claim. One-way ANOVA: Source DF SS MS F P Size 3 13.500 4.500 5.17 0.011 Error 16 13.925 0.870 Total 19 27.425 can you show how you worked it out please
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Perform a hypothesis test to determine whether there is a difference in the mean attendance of teams between the two groups created in Part F. Use a 0.05 level of significance in your testing procedures. Hint: When calculating your pooled sample variance and your test statistic, assume the Top 10 data is sample 1 and the Bottom 10 data is sample 2. Decision Rule -t < or t > = REJECT H0 Value of Pooled Sample Variances Value of test statistic Decision: enter Reject or Do Not Reject Is there a difference in the mean attendance between the two groups assuming a 0.05 level of significance? Enter Yes or No. Another variable that can impact attendance is the team's win-loss record. Teams that are winning more games are thought to have increased attendance as fans prefer to see their home team "win" rather than "lose" (although for some teams such as the Chicago Cubs, this is not always an established relationship!). Create 2 samples…
I need help finding the test statistic, p value, whether to reject or fail to reject and do the results support the belief in the problem. Thanks in advance for your help
Report an appropriate hypothesis test and use a 5% significance level. The alternative hypothesis for the One-way Anova F-test would be Group of answer choices Ha: Density affects firing temperature. Ha: Firing temperature affects density. Ha: Firing temperature does not affect density. Ha: Density does not affect firing temperature.
A researcher notes that there seems to be a difference in the prevalence of high blood pressure among college-educated individuals who consume low amounts of processed foods and the prevalence of individuals who only have a high school education and consume high amounts of processed foods. Use the appropriate hypothesis to test for the independence of the two independent variables presented here at the 5% significance level to ensure confounding has not influenced the study’s results. Then, interpret your response. Diet Low in Processed Foods Normal BP High BP Total College Education 124 55 179 High School Education 69 152 221 Total 193 207 400 Diet High in Processed Foods Normal BP High BP Total College Education 64 85 149 High School Education 98 153 251 Total 162 238 400 The chi square value of 37.724 is higher than the chi square value of 3.84; therefore, we can accept H0 at…

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