The minimum fatigue life of rivets in the fuselage of a certain type of aircraft i modeled with a two-parameter Weibull distribution (&=0). During accelerate testing for the purpose of certification and approval by the FAA, the mean value o minimum life is found to be 90 minutes and the coefficient of variation is 15%. The
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- Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma. Over a period of months, an adult male patient has taken 8 blood tests for uric acid. The mean concentration was x = 5.35 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with σ = 1.85mg/dl.(a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (b) What conditions are necessary for your calculations? (c) interpret your results in the context of this problem. (d)Sample size find the sample size necessary for a 95% confidence level maximal margin of error E=1.10 for the mean concentration of uric acid in this patient's blood.Total plasma volume is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 50 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that ? = 7.20 ml/kg for the distribution of blood plasma.Spray drift is a constant concern for pesticide applicators and agricultural producers. The inverse relationship between droplet size and drift potential is well known. The paper "Effects of 2,4-D Formulation and Quinclorac on Spray Droplet Size and Deposition"+ investigated the effects of herbicide formulation on spray atomization. A figure in a paper suggested the normal distribution with mean 1050 µm and standard deviation 150 µm was a reasonable model for droplet size for water (the "control treatment") sprayed through a 760 ml/min nozzle. USE SALT (a) What is the probability that the size of a single droplet is less than 1380 µm? At least 950 µm? (Round your answers to four decimal places.) less than 1380 μm at least 950 μm (b) What is the probability that the size of a single droplet is between 950 and 1380 µm? (Round your answer to four decimal places.) (c) How would you characterize the smallest 2% of all droplets? (Round your answer to two decimal places.) The smallest 2% of…
- The antibody production of 12 male red-winged blackbirds before and after receiving testosterone implants was compared. The units for antibody levels were natural log (10-3 optical density) per minute (In(mOD/min)). The mean change in antibody production was d = 0.056, and the standard deviation was sd = 0.225 If you were assigned the task of repeating this experiment, and wanted to ensure that you could detect a mean change of 0.02 units with a probability of 0.8, then what sample size would you use? Since we are calculating n for a study of individuals, answers should be rounded up to the next whole number.Please do a, e, and f onlyConsider the variable X whose mean and variance are given respectively by μx = 28.4 and Var(X) =8.6. Next consider the variable Y such that Y = 18.6 X-52 What is the mean of variable Y?
- H0 : =150.00 kPa H1 :>150.00 kPa b) α= 0.01; sample variance : 1300 freq. table sample deviation : 36.0555 freq. tableA statistics teacher taught a large introductory statistics class, with 500 students having enrolled over many years. The mean score over all those students on the first midterm was u = 88 with standard deviation o = 10. One year, the teacher taught a %3D much smaller class of only 25 students. The teacher wanted to know if teaching a smaller class was more effective and students performed better. We can consider the small class as an SRS of the students who took the large class over the years. The average midterm score was = 78. The hypothesis should be: a. Ho: H = 78 vs. Ha: H = 88. %3D O b. Ho: µ = 88 vs. Ha: µ 78 %3D Ο d. Ho: μ-88 νs. Ha: μ >88. %3DThe boiling point of 16 samples of a certain brand of hydrogenated vegetable oil used in a fryer was collected, resulting in Xbar=152.1 degrees. Assume that the distribution of melting point is normal with o=3.20. If the boiling point is different than 150 degrees, then either the oil will be too hot and will burn food or it will be too cool and will not properly cook the food. Is the sample mean significantly different from the target of 150 degrees? Use alpha=0.01 Но: H1: Define critical (rejection) region(s): Calculate the appropriate test statistic: What decision do we make? What this decision means in terms of this problem?
- A study was carried out to compare mean customer satisfaction scores at service centers in city A, in city B, and in city C. The sample means on a scale of 0 to 10 were 8.4 in city A, 8.6 in city B, and 7.9 in city C. Each sample size = 100, MS error = 0.41, and the F test statistic = 27.4 has P-value <0.001. Complete parts a through d. a. What is the margin of error for separate 95% confidence intervals? (For df = 297, 1.025 = 1.968.) margin of error = *** tv (Round to two decimal places as needed.) Clear all Check answer ST AThe level of calcium in the blood of healthy young adults follows a normal distribution with mean u = 10 milligrams per deciliter and standard deviation s = 0.4. A clinic measures the blood calcium of 100 healthy pregnant young women at their first visit for prenatal care. The sample mean of these 100 measurements is X = 9.8. Is this evidence that the mean calcium level in the population from which these women come is less than 10? To answer this question, we perform the following hypothesis test: H0: u = 10, Ha: u < 10. What is the test statistic? (use two decimal places in your answer) What is the p-value equal to? At the 10% significance level, do you accept or reject the null hypothesis? Answer ACCEPT or REJECT t the 5% significance level, do you accept or reject the null hypothesis? Answer ACCEPT or REJECTCalcium is essential to tree growth. In 1990, the concentration of calcium in precipitation in a certain area was 0.11milligrams per liter (mg/L).A random sample of 10 precipitation dates in 2018 results in the following data table. Complete parts (a) through (c) below. (B) With 98% confidence, the mean concentration of calcium in precipitation in this area in 2018 is between