The antibody production of 12 male red-winged blackbirds before and after receiving testosterone implants was compared. Theunits for antibody levels were natural log (10-3 optical density) per minute (In(mOD/min)). The mean change in antibody productionwas d = 0.056, and the standard deviation was sd = 0.225Ifyou were assigned the task of repeating this experiment, and wanted to ensure that you could detect a mean change of 0.02units with a probability of 0.8, then what sample size would you use?Since we are calculating n for a study of individuals, answers should be rounded up to the next whole number.

Answered: Image /qna-images/answer/c23ba28c-9abf-4aa4-9b6d-74d6396830c4.jpg

Answered: The antibody production of 12 male…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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It takes an average of 13.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 67 injured patients to immediately tell the truth about the injury and noticed that they averaged 15.7 minutes for their blood to begin clotting after their injury. Their standard deviation was 4.88 minutes. What can be concluded at the the αα = 0.05 level of significance? The null and alternative hypotheses would be: H0=? H1=? The test statistic = ? (please show your answer to 4 decimal places.) The p-value =? (Please show your answer to 5 decimal places.)
It takes an average of 12.9 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 47 injured patients to immediately tell the truth about the injury and noticed that they averaged 11.2 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.79 minutes. What can be concluded at the the αα = 0.10 level of significance?
Does increased sleep lead to better SAT scores? A sample of 11 participants slept for at least 10 hours before taking the SAT. The sample's SAT scores were compared to the national average SAT score (population mean). Analyses found that participants in the sample had significantly higher SAT scores compared to the population, with t-statistic = 2.00. How much of the variance in SAT scores was explained by increasing sleep?
Two of the hottest smartphones on the market are the newly released iPhone6 and the Samsung Galaxy S6. CNet.com offers online reviews of all major cell phones, including battery life tests. In a review of the iPhone6, the talk-time battery life of 35 iPhones was measured. Similarly, the talk-time battery life of 30 Galaxy S6s was measured. Two outputs are given below. Which is appropriate for analyzing the data collected? Output 1 lhi Mean of iPhone6 Hz : Mean of Galaxy S6 Sam ple Diff. Output 2 HR = mean of the paired difference between iPhone6 and Galaxy S6 Difference Std. Err. Difference Sam ple Diff. Std. Err. H1 - Hz -0.71759861 0.189403 iPhone6 - Galaxy S6 -0.754246 0.192151 Possible p-values: 0.0001, 0.0002, 0.9999 Possible p-values: 0.0002, 0.0004, 0.9998 OOutput 1 Output 2 Using the StatCrunch output chosen above, determine if there is a difference in the mean battery life for the two phones. Use a significance level of 0.01 when conducting the test. • Select the appropriate…
Archives of the Journal of Internal Medicine claimed that garlic has no effect on blood cholesterol, in other words than the mean drop in cholesterol after treating with raw garlic is 0.0 mg/dL. A clinical trial involving 36 subjects was conducted to test the effectiveness of garlic for lowering cholesterol. The sample mean for the drop in cholesterol was 3.5 mg/dL with a standard deviation of 18.0 mg/dL. Complete the following steps using α=0.01 level of significance to test whether the mean drop in cholesterol is greater than 0.0 mg/dL when treating with raw garlic. (NOTE: All areas are to be reported to four decimal places; all z-scores are reported to two decimal places except the two special cases listed at the bottom of the table.) Insert the following values from the question: μ = Answermg/dL x̅ = Answermg/dL σ = Answermg/dL n = Answer subjects α = Answer Set up the hypothesis statements (no spaces between characters): H0: Answer H1: Answer Based on the hypothesis…
It takes an average of 9.1 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 45 injured patients to immediately tell the truth about the injury and noticed that they averaged 9.1 minutes for their blood to begin clotting after their injury. Their standard deviation was 0.91 minutes. What can be concluded at the the αα = 0.10 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = H1:H1: ? μ p Select an answer = < ≠ > The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept fail to reject reject…
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
It takes an average of 9.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 52 injured patients to immediately tell the truth about the injury and noticed that they averaged 10.7 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.98 minutes. What can be concluded at the the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean, z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer = ≠ < > H1:H1: ? p μ Select an answer < ≠ > = The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept…
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.8 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 242samples is 5.2 ppm with a variance of 1.001.00. Does the data support the claim at the 0.05 level? Assume the population distribution is approximately normal. Find the value of the test statistic. Round your answer to three decimal places. Specify if the test is one-tailed or two-tailed. Determine the decision rule for rejecting the null hypothesis. Round your answer to three decimal places. Make the decision to reject or fail to reject the null hypothesis.
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.97.9 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 2424 samples is 8.18.1 ppm with a variance of 0.250.25. Does the data support the claim at the 0.10.1 level? Assume the population distribution is approximately normal. Step 3 of 5: Specify if the test is one-tailed or two-tailed.
It takes an average of 14.5 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 65 injured patients to immediately tell the truth about the injury and noticed that they averaged 15.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.05 minutes. What can be concluded at the the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly greater than 14.5 at αα = 0.05, so there is statistically significant…
It takes an average of 10.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 46 injured patients to immediately tell the truth about the injury and noticed that they averaged 11.7 minutes for their blood to begin clotting after their injury. Their standard deviation was 2.98 minutes. What can be concluded at the the αα = 0.05 level of significance? The null and alternative hypotheses would be: Please provide number H0:H0: mean =Correct __?__ H1:H1: mean > Correct_ __?__ The test statistic t = __?__ (please show your answer to 3 decimal places.) The p-value = __?__ (Please show your answer to 4 decimal places.)

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