It takes an average of 12.6 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 67 injured patients to immediately tell the truth about the injury and noticed that they averaged 12.9 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.86 minutes. What can be concluded at the α = 0.05 level of significance? For this study, we should use Select an answer z-test for a population mean t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer ≥ ≠ ≤ = > < H1:H1: ? p μ Select an answer = > ≥ ≤ ≠ < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > α Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly greater than 12.6 at αα = 0.05, so there is enough evidence to conclude that the population mean time for blood to begin clotting after an injury if the patient is told the truth immediately is greater than 12.6. The data suggest that the population mean is not significantly greater than 12.6 at αα = 0.05, so there is not enough evidence to conclude that the population mean time for blood to begin clotting after an injury if the patient is told the truth immediately is greater than 12.6. The data suggest the population mean is not significantly greater than 12.6 at αα = 0.05, so there is enough evidence to conclude that the population mean time for blood to begin clotting after an injury if the patient is told the truth immediately is equal to 12.6.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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It takes an average of 12.6 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 67 injured patients to immediately tell the truth about the injury and noticed that they averaged 12.9 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.86 minutes. What can be concluded at the α = 0.05 level of significance?

For this study, we should use Select an answer z-test for a population mean t-test for a population mean
The null and alternative hypotheses would be:

H0:H0: ? p μ Select an answer ≥ ≠ ≤ = > <

H1:H1: ? p μ Select an answer = > ≥ ≤ ≠ <

The test statistic ? z t = (please show your answer to 3 decimal places.)
The p-value = (Please show your answer to 4 decimal places.)
The p-value is ? ≤ > α
Based on this, we should Select an answer reject fail to reject accept the null hypothesis.
Thus, the final conclusion is that ...
- The data suggest the populaton mean is significantly greater than 12.6 at αα = 0.05, so there is enough evidence to conclude that the population mean time for blood to begin clotting after an injury if the patient is told the truth immediately is greater than 12.6.
- The data suggest that the population mean is not significantly greater than 12.6 at αα = 0.05, so there is not enough evidence to conclude that the population mean time for blood to begin clotting after an injury if the patient is told the truth immediately is greater than 12.6.
- The data suggest the population mean is not significantly greater than 12.6 at αα = 0.05, so there is enough evidence to conclude that the population mean time for blood to begin clotting after an injury if the patient is told the truth immediately is equal to 12.6.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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