The metabolism of Cpd C (C18H28O2) can be written as -12000 kJ/mol C18H2802(s) + 24 O2(g) glucose 18 CO2(g) + 14 H2O1) AG° %3D Synthesis of ATP can be written as ADP(aq) + PO4° (aq) 3- ATP(ag) + H2O(1) AG° = + 31 kJ/mol ATP Using the data in this problem, how many mol of ATP (to the nearest whole number) can be made from the metabolism of 1 mol of Cpd C? 323 mol ATP/mol Cpd C 90 mol ATP/mol Cpd C 387 mol ATP/mol Cpd C none of the answers are correct

The metabolism of Cpd C (C18H28O2) can be written as -12000 kJ/mol C18H2802(s) + 24 O2(g) glucose 18 CO2(g) + 14 H2O1) AG° %3D Synthesis of ATP can be written as ADP(aq) + PO4° (aq) 3- ATP(ag) + H2O(1) AG° = + 31 kJ/mol ATP Using the data in this problem, how many mol of ATP (to the nearest whole number) can be made from the metabolism of 1 mol of Cpd C? 323 mol ATP/mol Cpd C 90 mol ATP/mol Cpd C 387 mol ATP/mol Cpd C none of the answers are correct

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For the following reactions, indicate whether the entropy of the system increases, decreases, or remains nearly the same. ( Circle) a) Al3* (aq) + 3 OH" (aq) → Al(OH)3 (s) increase decrease remains nearly the same b) CaCO3(s) → CaO(s) + CO2(g) increase decrease remains nearly the same c) Mg(s) + Cu2+(aq) → Mg²*(aq) + Cu(s) increase decrease remains nearly the same Rank the compounds in each of the following groups in order of increasing standard molar entropy. a) CHa(g), CF4(g), CCI1(g) b) CH20(g), CH3CHO(g), CH3CH2CHO (g). c) HF(g), H20(g), NH3(g).
Here are some relevant excerpts from the tables of standard thermodynamic data: Substance ΔHfo(kJ/mol) H2O (l) -286 NO (g) 90 NO2 (g) 34 HNO3 (aq) -207 NH3 (g) -46 Find ΔHo in kJ of 4NH3(g) + 5 O2 (g) --> 4 NO (g) + 6 H2O (l) Question 15 options: -1540 kJ -1172 kJ -1892 kJ -150 kJ
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Species ΔGo Fe(OH)3 -696.5 Fe3+ -4.6 OH- -157.3 Calculate the ΔGo of the reaction: Fe(OH)3(s) ↽−−⇀ Fe3+(aq) + 3 OH-(aq) T = 25o C Express the answer to 1 decimal place.
From the enthalpies of reaction 2C(s) + O2 (9) → 2C0(g) 2C(s) + O2 (9) + 4H2 (g) → 2CH3 OH(g) AH ΔΗ :-221.0kJ %3| :-402.4kJ calculate AH for the reaction CO(g) + 2H2 (g) → CH3 OH(g) Express your answer to three significant figures with the appropriate units.
A critical reaction in the production of energy to do work or drive chemical reactions in biological systems is the hydrolysis of adenosine triphosphate, ATP, to adenosine diphosphate, ADP, as described by the reaction ATP(aq) + H,O(1) → ADP(aq) + HPO (aq) for which AGixn = -30.5 kJ/mol at 37.0 °C and pH 7.0. Calculate the value of AGxn in a biological cell in which [ATP] = 5.0 mM, [ADP] = 0.40 mM, and [HPO?-] = 5.0 mM. AGxn kJ/mol %3D Is the hydrolysis of ATP spontaneous under these conditions? O yes
2. Given the following data V(s) + 2 Cl₂(g) → VC14 (1) 1 VCl3(s) → VCl2 (s) + 2 Cl2(g) 2 VC13(s) → VCl₂ (s) + VC14 (1) calculate AH for the reaction: [-580.7 kJ] 3 V(s) + Cl2(g) → VCl3 (s) 2 AH= -569.4 kJ AH = +128.9 kJ ΔΗ = +140.2 kJ I
18. Calculate the AH of reaction for CIF(g)F2(g)> CIF3(g) given the following data: 1) 2CIF(g)O2(g) -> Cl20(g) +F20(g) ΔΗ -167.4 kJ 2) 2CIF3(g)202(g)Cl20(g) +3 F2O(g) ΔΗ-341.4 kJ 3) 2F2(g)O2(g)->2F20(g) AH -43.4 kJ a. -217 kJ b. 465 kJ c. -174 kJ d. 233 kJ е. -109 kJ
Consider the reaction 2NaOH(aq) + H2(g)—2Na(s) + 2H2O(l) for which AH° = 368.6 kJ and AS° = 15.30 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.759 moles of NaOH(aq) react under standard conditions at 298.15 K. ASuniverse= J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'. Submit Answer
Calculate AHrxn for the reaction below. 2 NOCI(g) → N2(g) + 02(g) + Cl2(9) You are given the following set of reactions. 1/2 N2(g) + 1/2 02(g) → NO(g) AH = 90.30 k) NO(g) + 1/2 Cl2(g) → NOCI(g) AH = -38.6 kJ 4.0 kJ
(Q70) Using the tabulated values from the text (located in Appendix G, beginning at p. 1211) calculate (and report in kJ) the standard Gibbs free energy (AG°rxn) for the net reaction that occurs during photosynthesis: 6 H2O (1) + 6 CO2 (g) --> C6H12O6 (s) + 6 O2 (g). The AG°; for glucose (C6H1206) is -1273.3 kJ/mol.