4AI203 + 3CH4→ 8AI + 3CO2 + 6H20 AH° rxn kJ exo ? endo thermic AH° = -1676 -75 -394 -242 kJ/mol MnO2(s) + 2CO(g) → Mn(s) + 2CO2(g) AH°xn = kJ exo ? endo thermic AH° = -520 -111 -394 kJ/mol CF4(g) + 2H2O(g) → CO2(s) + 4HF(g) AH°rxn kJ exo ? endo thermic AH° = -934 -242 -394 -273 kJ/mol

4AI203 + 3CH4→ 8AI + 3CO2 + 6H20 AH° rxn kJ exo ? endo thermic AH° = -1676 -75 -394 -242 kJ/mol MnO2(s) + 2CO(g) → Mn(s) + 2CO2(g) AH°xn = kJ exo ? endo thermic AH° = -520 -111 -394 kJ/mol CF4(g) + 2H2O(g) → CO2(s) + 4HF(g) AH°rxn kJ exo ? endo thermic AH° = -934 -242 -394 -273 kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

6. Use the molar AHf under formulas to calculate AH°,
xn for the equations as balanced:
4Al203 + 3CH4
— 8А1 + 3CО2 + 6H20
ΔΗn
kJ
exo ? endo thermic
AH° = -1676 -75
-394
-242 kJ/mol
MnO2(s) + 2CO(g) → Mn(s) + 2CO2(g) AH°rxn =
kJ
exo ? endo thermic
AH° = -520
-111
-394 kJ/mol
CF4(g) + 2H20(g) → CO2(s) + 4HF(g)_ AH°rxn
kJ
exo ? endo thermic
AH° = -934 -242
-394
-273 kJ/mol

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