The material for the bolt shown in Figure 2, the angled joint has an ultimate tensile strength of 600MPa and shear strength of 300 MPa. The diameter of the bolt is 10 mm. Determine the factor of safety.Assume force of F = 25 kN.F+60%Figure. 2F

Step 1: Step 2: Step 3: Step 4:

Answered: The material for the bolt shown in…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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. A machine member is subjected to fluctuating stress 0=0, cos(8nt). The endurance limit of the material is 350 MPa. If the factor of safety used in the design is 3.5, then the maximum allowable value of o, is MPa (round off to 2 decimal places). 0
b-Yield strength using 0.006 extension strain method (in psi). Answer: c- If the yield stress is considered failure stress, what is the maximum working stress (psi) to be applied to this material if a factor of safety of 1.25 is used? Answer:
If a key material has an ultimate strength of 120 ksi and a yield strength of 80 ksi and factor of safety N=2, what would be the design compressive stress in ksi? (a) 40 ksi (b) 60 ksi (c) 160 ksi (d) 240 ksi
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Example 7 The joint shown is fastened together using two bolts. Determine the required diameter of the bolts if the failure shear stress for the bolts is fail = 350 MPa. Use a factor of safety for shear of 2.5. [Answer: d = 13.5mm.] 40 KN 40 kN 30 mm 80 KN 30 mm
A cylindrical metal rod of 20mm diameter and 1m length is subjected to a tensile load of 60KN. To what length the cylinder should be centrally bored on one side to reduce weight by material removal, so that the total extension will increase by 10 percent under the same pull. The diameter of the hole being bored on one side is equal to 10mm. Take E= 200GPa.
Please solve all the question handwritten
A 30-mm thick AISI 1020 steel plate is sandwiched between two 10-mm thick 2024-T3 aluminum plates and compressed with a bolt and nut with no washers. The bolt is M10 x 1.5. property class 5.8. (a) Determine a suitable length for the bolt, rounded up to the nearest 5 mm. (b) Determine the bolt stiffness. (c) Determine the stiffness of the members.
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A bar of circular cross-section is subjected to alternating tensile forces varying from a minimum of 200 kN to a maximum of 500 kN. It is to be manufactured of a material with an ultimate tensile strength of 900 MPa and an endurance limit of 700 MPa. Determine the diameter of bar using safety factors of 3.5 related to ultimate tensile strength and 4 related to endurance limit and a stress concentration factor of 1.65 for fatigue load. Use Goodman straight line as basis for design.” [1]
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The material for the bolt shown in Figure 2, the angled joint has an ultimate tensile strength of 600 MPa and shear strength of 300 MPa. The diameter of the bolt is 10 mm. Determine the factor of safety. Assume force of F = 25 kN. F+ 60% Figure. 2 F