The lowest triplet state in naphtnalene (C10H8) is about below thne lowest excited by N2/N1 = (92/91)exp(-AE/kgT), where g1 and g2 are the degeneracies for levels 1 and 2.] N2 = 1.43e-90
Electronic Transitions and Spectroscopy
The term “electronic” connotes electron, and the term “transition” implies transformation. In a molecule, the electrons move from a lower to a higher energy state due to excitation. The two energy states, the ground state and the excited state are the lowest and the highest energy states, respectively. An energy change is observed with this transition, which depicts the various data related to the molecule.
Photoelectron Spectroscopy
Photoelectron spectroscopy (PES) is a part of experimental chemistry. It is a technique used in laboratories that involves projecting intense beams of radiation on a sample element. In response, the element ejects electrons for which the relative energies are measured.
![The lowest triplet state in naphthalene (C10H8) is about 11,000 cm-1 below the lowest excited singlet electronic level at 77 K. Calculate the ratio of populations in these two states at equilibrium. [Hint: The Boltzmann equation is given
by N2/N1 = (g2/g1)exp(-AE/kBT), where g1 and g2 are the degeneracies for levels 1 and 2.]
N2
1.43e-90
N1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F558e69fb-bdf7-44c8-8f73-38112cc2ca63%2F326e11ad-b6b5-4f38-ab4d-484a8e46b143%2F3vvci4j_processed.png&w=3840&q=75)
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