-10(number in bracket)The bond length of the CN molecule is 1.3 x 10m. Given RAM:C = 12.0, N = 14.0, calculate (to 3 sig. fig.): (NOTE: exp = x 1021. The moment of inertia, I 1.81 exp(-45) v kg m2. The rotational constant B-1m-13. The position (in m ') of the 2.62 exp(-18)tional spectrum of this molecule.1551.553.28 exp(-10) -10(number in bracket),The bond length of the CN molecule is 1.3 x 10m. Given RAM: C = 12.0, N = 14.0, calculate (to 3 sig. fig.): (NOTE: exp = x 1021. The moment of inertia, I 1.81 exp(-45)kg m-12. The rotational constant B3. The position (in m ) of the first line in the rotational spectrum of this molecule.0.77515577.5310

We have to predict the moment of inertia, rotational constant, position of first rotational line.

(number in bracket), he bond length of the CN molecule is 1.3 × 10 -10 m. Given RAM: C = 12.0, N = 14.0, calculate (to 3 sig. fig.): (NOTE: exp = × 10' 2 - The moment of inertia, I 1.81 exp(-45) kg m . The rotational constant B -1 m - The position (in m ') of the 2.62 exp(-18) tional spectrum of this molecule. 155 1.55 3.28 exp(-10)

(number in bracket), he bond length of the CN molecule is 1.3 × 10 -10 m. Given RAM: C = 12.0, N = 14.0, calculate (to 3 sig. fig.): (NOTE: exp = × 10' 2 - The moment of inertia, I 1.81 exp(-45) kg m . The rotational constant B -1 m - The position (in m ') of the 2.62 exp(-18) tional spectrum of this molecule. 155 1.55 3.28 exp(-10)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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