The left beaker contains 9mM NaCl and 9mM glucose solution.The right beaker contains distilled water.The molecular weight of NaCl is 58.44 g/mol. The molecular weight of glucose is 180.16 g/mol. The membrane located between the two beakers is impermeable to NaCl and glucose. The membrane is permeable to H2O. What will occur across the membrane?

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The left beaker contains 9mM NaCl and 9mM glucose solution.The right beaker contains distilled water.The molecular weight of NaCl is 58.44 g/mol. The molecular weight of glucose is 180.16 g/mol. The membrane located between the two beakers is impermeable to NaCl and glucose. The membrane is permeable to H2O. What will occur across the membrane?

9 mM NaCl
Membrane
9 mM glucose
Left
Distilled
H₂O
Right
NaCl will diffuse across the membrane from the left to the right beaker until an equilibrium is reached.
Water will move via osmosis across the membrane from the right to the left beaker. The pressure in the left beaker will increase.
O Water will move via osmosis across the membrane from the left to the right beaker. The pressure in the right beaker will increase.
O Both NaCl and glucose will diffuse across the membrane from the left to the right beaker until an equilibrium is reached.
Transcribed Image Text:9 mM NaCl Membrane 9 mM glucose Left Distilled H₂O Right NaCl will diffuse across the membrane from the left to the right beaker until an equilibrium is reached. Water will move via osmosis across the membrane from the right to the left beaker. The pressure in the left beaker will increase. O Water will move via osmosis across the membrane from the left to the right beaker. The pressure in the right beaker will increase. O Both NaCl and glucose will diffuse across the membrane from the left to the right beaker until an equilibrium is reached.
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