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The individual is heterozygous for genes H and F, and their alleles are in cis. Draw alleles on homologous chromosome
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- In Drosophila, the white gene located on the X chromosome affects eye color; an autosomal gene, wingless, is on an autosomal chromosome. Use the following allele symbols: Xw+ _ , Xw+Y = wild type red eyes; X-linked dominant allele Xw Xw , XwY = white eyes; X-linked recessive allele Y = Y sex chromosome vg+ = wild type wings; autosomal dominant vg = wingless; autosomal recessive Predict ratios/proportions of genotypes and phenotypes of offspring from the following cross, of a white-eyed male with wild type wings and a wild type red eyed female with wild type wings: indicate sex of offspring along with phenotypes. XwY vg+ vg x Xw+Xw vg+vgAn allele that is not expressed in the heterozygous condition isAn individual has the genotype AabbCC. The A gene is located on chromosome 1 while the B and C genes are located on chromosome 2. Draw the homologous pairs for both chromosome 1 and chromosome 2 and label the genes/alleles on each.
- In Drosophila, the gene for red and white eye colour is found on the X chromosome. The allele for red eyes (XR) is dominant to the allele for white eyes (Xr). A heterozygous red-eyed female fruit fly was crossed with a white-eyed male fruit fly. Complete the following Punnett square for this cross. Answer Answer Answer Answer Answer Y Answer AnswerA heterozygous null (X*/XA) is most likely to have what type of phenotype: mutant O wild-typeTwo people are planning to have children together. Each person is heterozygous for the gene “G”. Using this letter, first list all the possible gametes that the two people can produce. Next, write all the possible genotypes and phenotypes for their offspring, using the correct genetic terminology (e.g., “genotype is homozygous dominant” “phenotype is dominant”). HINT: Use the gametes to construct a Punnett square and predict the possible offspring (you do not need to include the Punnett square in your answer
- Draw a Punnett square for the dihybrid cross. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage.In Drosophila, singed bristles (sn) and cut wings (ct) are both caused by recessive, X-linked alleles. The wild type alleles (sn+ and ct+) are responsible for straight bristles and intact wings, respectively. A female homozygous for sn and ct+ is crossed to a sn+ct male. The F1 flies are interbred. The F2 males are distributed as follows: genotype number sn ct 15 sn ct+ 34 sn+ ct 33 sn+ct+ 18 What is the map distance between sn and ct?Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?
- Human sex chromosomes are XX for females and XY for males. a. With respect to an X-linked gene, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele? c. If a female is heterozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele?Two people are planning to have children together. Each person is heterozygous for the gene “A”. Using this letter, first list all the possible gametes that the two people can produce. Next, write all the possible genotypes and phenotypes for their offspring, using the correct genetic terminology (e.g., “genotype is homozygous dominant” “phenotype is dominant”). HINT: Use the gametes to construct a Punnett square and predict the possible offspring (you do not need to include the Punnett square in your answer).In sweet pea, gene C or P alone produces white flowers, the purple color being due to the presence of both of these factors. A white-flowered plant crossed with a purple produces progeny of which 3/8 are purple and 5/8 are white-flowered plants. Give the genotypes of the parents and offspring.
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