The Henderson-Hasselbalch Equation Given the equilibrium acid dissociation constant Ka Derive the Henderson-Hasselbalch equation - [H+][A-] [HA] [A-] [HA] Recall that the p-scale is defined as the log. Hence, pH means - log [H+] and pKa means - log Ka. pH = pKa + log

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### The Henderson-Hasselbalch Equation

#### Given the equilibrium acid dissociation constant

\[ K_a = \frac{[\text{H}^+][\text{A}^-]}{[\text{HA}]}\]

#### Derive the Henderson-Hasselbalch equation

\[ \text{pH} = \text{p}K_a + \log \left(\frac{[\text{A}^-]}{[\text{HA}]}\right)\]

#### Recall that the p-scale is defined as the \(-\log\). Hence, \(\text{pH}\) means \(-\log [\text{H}^+]\) and \(\text{p}K_a\) means \(-\log K_a\).
Transcribed Image Text:### The Henderson-Hasselbalch Equation #### Given the equilibrium acid dissociation constant \[ K_a = \frac{[\text{H}^+][\text{A}^-]}{[\text{HA}]}\] #### Derive the Henderson-Hasselbalch equation \[ \text{pH} = \text{p}K_a + \log \left(\frac{[\text{A}^-]}{[\text{HA}]}\right)\] #### Recall that the p-scale is defined as the \(-\log\). Hence, \(\text{pH}\) means \(-\log [\text{H}^+]\) and \(\text{p}K_a\) means \(-\log K_a\).
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