Calculate the pH and concentrations of CH,NH, and CH,NH† in a 0.0407 M methylamine (CH,NH,) solution. The K, of CH;NH, is 4.47 × 10-4.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem Statement:**

Calculate the pH and concentrations of CH₃NH₂ and CH₃NH₃⁺ in a 0.0407 M methylamine (CH₃NH₂) solution. The Kb of CH₃NH₂ is 4.47 × 10⁻⁴.

**Solution Fields:**

- **pH =** [Enter calculated value here]

- **[CH₃NH₂] =** [Enter calculated concentration here] M

- **[CH₃NH₃⁺] =** [Enter calculated concentration here] M 

**Explanation:**

To solve this problem, you will need to:

1. Use the given Kb value for methylamine to find the concentrations of CH₃NH₂ and CH₃NH₃⁺.
2. Apply the formula for base dissociation to determine the hydroxide ion (OH⁻) concentration.
3. Convert the OH⁻ concentration to pH.
Transcribed Image Text:**Problem Statement:** Calculate the pH and concentrations of CH₃NH₂ and CH₃NH₃⁺ in a 0.0407 M methylamine (CH₃NH₂) solution. The Kb of CH₃NH₂ is 4.47 × 10⁻⁴. **Solution Fields:** - **pH =** [Enter calculated value here] - **[CH₃NH₂] =** [Enter calculated concentration here] M - **[CH₃NH₃⁺] =** [Enter calculated concentration here] M **Explanation:** To solve this problem, you will need to: 1. Use the given Kb value for methylamine to find the concentrations of CH₃NH₂ and CH₃NH₃⁺. 2. Apply the formula for base dissociation to determine the hydroxide ion (OH⁻) concentration. 3. Convert the OH⁻ concentration to pH.
Expert Solution
Step 1

CH3NH2 is a weak base. In water, the following equilibrium reactions happens:

Chemistry homework question answer, step 1, image 1

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