An acid (HA) dissociates as follows: HA → H* + A minus Arrow should be interpreted as an equilibrium arrow. The pH of the 0.81 M solution of HA is 1.46. What is the K, of HA? Express your answer as a decimal, not an exponent. No unit, please. Your Answer:

An acid (HA) dissociates as follows: HA → H* + A minus Arrow should be interpreted as an equilibrium arrow. The pH of the 0.81 M solution of HA is 1.46. What is the K, of HA? Express your answer as a decimal, not an exponent. No unit, please. Your Answer:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: Determine the pH of the solution. (2 decimals) 0.21 M KCHO 2 (Ka(HCHO₂)=1.8x10-4)

A: Answer:When salt of weak acid and strong base is added in water, due to hydrolysis it produces OH-…

Q: Determine the pH and percent ionization for a hydrocyanic acid (HCN) solution of concentration 1.6 x…

A: Given: Concentration of HCN = 0.0016 M And Ka of HCN = 4.9 × 10-10 The…

Q: Given a solution with a concentration of 1x 10^-3 M, what is the pH? Is the solution acidic or…

A: pH = -log[H+] pH<7 , solution is acidic pH>7, solution is basic pH = 7 , solution is neutral…

Q: For the acid HNO2 identify its conjugate base, write the dissociation reaction and write the acid…

A: Bronsted-Lowry concept of an acid and base, the conjugate base can be differentiated by a proton as;…

Q: An acid (HA) dissociates as follows: HA → H* + A minus Arrow should be interpreted as an equilibrium…

Q: 0.85 g of hydrogen chloride (HCI) is dissolved in water to make 7.5 L of solution. What is the pH of…

Q: An acid (HA) dissociates as follows: HA – H* + A minus Arrow should be interpreted as an equilibrium…

A: The equilibrium reaction given is, => HA --------> H+ + A- Given : Initial concentration of…

Q: An acid (HA) dissociates as follows: HA → H* + A minus Arrow should be interpreted as an equilibrium…

A: Given :- HA <-----> H+ + A- Initial concentration of HA = 0.37 M pH = 4.91 To be…

Q: Determine the pH of a 0.25 M NH3 solution. Round your answer to 2 decimal places. Note: K for NH₂ is…

Q: An acid (HA) dissociates as follows: НА - H* + A minus Arrow should be interpreted as an equilibrium…

Q: Consider the following data on some weak acids and weak bases: acid name formula hypochlorous acid…

A: The objective of the question is to rank the given solutions in the increasing order of the pH-

Q: What is the pH of a neutral solution at 10°C, where Ku equals 3.6 × 10-18? pH =

A: Given : Kw at 10 oC = 3.6 X 10-15 Since in neutral solution, the equilibrium reaction taking place…

Q: Consider the following data on some weak acids and weak bases: name acid formula nitrous acid HNO₂…

A: The question is based on the concept of acidity. we need to arrange the given salts in order of…

Q: Enter your answer in the provided box. Calculate the pH of a 0.028 M Ba(OH)2 solution. pH =

A: We know that pH of solution can be calculate as pH=14-pOHwhere pOH=-logOH- Given solution is…

Q: A solution of HCN was prepared in 2.5 L of water. The pH of this solution at 25°C was determined to…

A: We have to calculate the moles of HCN.

Q: Construct the expression for Ka for the weak acid, NH4+. NH4+ (aq) + H₂O(1) H3O+ (aq) + NH3(aq) 1…

A: Acid dissociation constant (Ka): it can be define as an equilibrium constant which is related to the…

Q: Consider the following data on some weak acids and weak bases: name acetic acid hydrofluoric acid…

A: The question is based on the concept of pH of the solution.It is defined as a negative logarithm of…

Q: A solution that has a hydrogen ion concentration equal to 9.61 x 10-7 has a pH =

Q: The K for benzoic acid is 6.5 × 10 pH = Calculate the pH of a 0.27 M benzoic acid solution. Round…

A: 1st) Construct ICE table to obtain their equilibrium concentrations:2nd) Write Equilibrium…

Q: An acid (HA) dissociates as follows: HA - H* + A minus Arrow should be interpreted as an equilibrium…

Q: What is the pH of 425.0 mL of an aqueous solution containing 0.559 g of HCI? Round your answer to 3…

A: Volume= 425 ml 1 L = 1000 ml so 425 ml =0.425 L Volume= 0.425 L Weight of HCl = 0.559 gram.…

Q: the pH of a mysterious solution has an H+ concentration of: 1.704 x 10-2 is. After finding the pH,…

Q: Construct the expression for Ka for the weak acid, CH,COOH. CH,COOH(aq) + H,O(1) = H,O*(aq) +…

A: Given data :

Q: An acid (HA) dissociates as follows: HA – H* + A minus Arrow should be interpreted as an equilibrium…

Q: Determine both the H and the pH in a 0.0541 M solution of HNO3 at 25 °C? H= Type your answer here…

A: The concentration of HNO3 solution = 0.0541 M HNO3 → H+ + NO3− The concentration of H+, [H+] =…

Q: Determine the pH of a 0.62 M NH,NO3 solution at 25°C. The K, for NH3 is 1.8 x 10-5. Express your…

Q: Calculate the pH of a 6.2 x 10-8 M HCl solution. Report your answer to the hundredths place. pH =…

Q: Consider the following data on some weak acids and weak bases: name 0.1 M KCI acid hydrocyanic acid…

A: Given,The solutions: Solution pH 0.1 M KCl…

Q: An acid (HA) dissociates as follows: HA - H* + A minus Arrow should be interpreted as an equilibrium…

A: Given that, HA ----> H+ + A- [HA] = 0.11M , pH=4.80 Then,

Q: At 25 °C, how many dissociated OH ions are there in 1247 mL of an aqueous solution whose pH is 1.97?…

A: Given that At 25 °C, pH of the aqueous solution= 1.97 Volume of the solution= 1247 mL

Q: The pH of an aqueous solution of 0.180 M potassium cyanide, KCN, is 8.93 (Assume that K₂ (HCN) =…

A: KCN dissociates in solution as KCN ---> K+ + CN-[ CN- ] = [ KCN ] = 0.180 MCN- hydrolyzed as CN-…

Q: Calculate the K₂ for a monoprotic acid, HX, if a 0.100000 M solution has a pH of 3.333. The data is…

A: The given reaction is : HX + H2O ⇔ X- + H3O+ The answer is as follows:

Q: sure your answer has the correct number of significant digits. Calculating the pH of a strong base…

A: Given : Mass of Barium hydroxide = 216. mg Volume of solution = 190. ml

Q: What is the pH of a 0.036 M aqueous solution of sodium cyanide, NaCN? The Ka of HCN is 4.9x10-10.…

A: the pH of a 0.036 M aqueous solution of sodium cyanide can be calculated as follows

Q: The pH of a 0.30 M solution of a weak base B is 10.22. What is the K, of the base? Be sure your…

A: From the given pH, we will get concentration of [H+] and from that concentration of [OH-]. And…

Q: Calculate the pH of a 0.20 mol/L solution of benzoic acid. Ka(benzoic acid) = 6.25×10-5 Express…

Q: Calculate the pH of a formic acid solution that contains 1.42% formic acid by mass. (Assume a…

A: Molarity of formic acid, C = moles of solutevolume of solution = 1.42 x 1.01 x 100046 x 100 = 0.312…

Q: An acid (HA) dissociates as follows: HA → H+ + A minus Arrow should be interpreted as an…

A: [H+] can be calculated by using formula

Q: The Kw for water at 0 °C is 0.12 × 10-14. Calculate the pH of a neutral aqueous solution at 0 °C. pH…

Question

An acid (HA) dissociates as follows:

\[ \text{HA} \rightleftharpoons \text{H}^+ + \text{A}^- \]

Arrow should be interpreted as an equilibrium arrow.

The pH of the 0.81 M solution of HA is 1.46.

What is the \( K_a \) of HA?

Express your answer as a decimal, not an exponent.

No unit, please.

Your Answer:
[Answer Box]

Expert Solution

Step 1 acid dissociation constant

Acid dissociation constant is commonly known as Ka , it measures the strength of acid in solution.

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

Calculate the pOH of a 0.05% HNO3 solution. (Densities: HNO3 = 1.51 g/cm, H20 = 1 g/cm ³) Enter the final answer with 2 decimal places.
Negative ions, designated by the notation [OH-] are always present in any acid or base. The concentration, [OH-], of these ions is related to [H*] by the equation [OH-] [H] = 10-14 moles per liter. Find the concentrations of [OH¯] and [H*] in moles per liter for the substances with the given pH value. pH = 12 ... The concentration of [H*] is moles per liter. (Type your answer using exponential notation.) The concentration of [OH-] is moles per liter. (Type your answer using exponential notation.)
I need help with these questions please!!
At 25 °C, how many dissociated H+ ions are there in 399 mL of an aqueous solution whose pH is 11.85? number of H+ ions: x10 TOOLS ions
Determine the OH- and H+ concentration and calculate the pH, pOH of a solution that is 0.70 M NH3 solution. NH3 + H2O <--> NH4 + + OH- Kb = 1.8 x 10-5
Morphine (C17H1903N) is very effective at relieving intense pain. Calculate the pH of a 0.00115 M solution of morphine. Kp = 8.0 x 10- (the answer should be entered with 3 significant figures; do not enter units; give answer in normal notation--examples include 1.23 and 120. and -123 and 123. and 12.3) MacBook Pro >) esc @ # & 1 3 4 7 8 Q W E R T. Y A S H J K C V option cоmmand command option .. .. V * 00
#8 - thumbs up if you do it correctly! Be sure your answer has the correct number of significant digits as it states in the directions.
Like all equilibrium constants, the value of Kw is temperature dependent. Kw is 1.47 x 10-14 at 30°C. What is "neutral" pH at this temperature (be sure to include 2 digits after the decimal in your answer)? pH= i (Tolerance is +/-2%)
Calculate the pH of a 0.060 M C₂H5N (pyridine) solution. The K, for pyridine is 1.7 x 10. Be sure your answer has the correct number of significant digits. pH = 0 x10 X
This is a multi- answer question. Please type your properly rounded answers in the next three questions ( starting with this one):Calculate the pH of a 0.70 M solution of sodium sulfite, Na2SO3. Also calculate the concentrations of HSO3 and H2SO3. Type the properly rounded pH below:
help please
For many weak acid or weak base calculations, you can use a simplifying assumption to avoid solving quadratic equations. x2 x- .2 [HА] — х [HA] Classify these situations by whether the assumption is valid or the quadratic formula is required. Assumption is valid Quadratic formula is required Answer Bank [HA] = 0.05 M Ka = 1 x 10-4 [HA] = 0.005 M Ka = 1 x 10-4 [НA] 3D 0.05 М Ka = 1 × 10-3 [HA] = = 0.005 M [HA] = 1 M Ką = 1 × 10-5 Ka = 1 × 10-3