The HbS gene produces sickle-shaped RBC in man. Its normal allele is called HbA. The incidence of Plasmodium falciparum (malaria) infection in African children is given below. Test whether the data conform to the hypothesis that heterozygotes are better protected against heavy malarial infection than normal HbA HbA homozygotes. Genotypes Heavy infection Noninfected/lightly infected 100 HbA HbŞ 36 HbA HbA 152 255
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- An individual has the following genotype. Gene loci (A) and (B) are 15 m.u. apart. What are the correct frequencies of some of the gametes that car be made by this individual? Bl a O A. Ab = 7.5%; AB = 42.5% B. ab = 25%; aB = 50% O C. AB = 7.5%; aB = 42.5% O D. aB = 15%; Ab = F0% E. aB = 70%; Ab = 15% Reset Selection OMark for Review What's This?Wild-type strains of the haploid fungus Neurospora canmake their own tryptophan. An abnormal allele td renders the fungus incapable of making its own tryptophan.An individual of genotype td grows only when its medium supplies tryptophan. The allele su assorts independently of td; its only known effect is to suppress the tdphenotype. Therefore, strains carrying both td and su donot require tryptophan for growth.a. If a td ; su strain is crossed with a genotypically wildtype strain, what genotypes are expected in the progenyand in what proportions?b. What will be the ratio of tryptophan-dependent totryptophan-independent progeny in the cross of part a?It says to sort the following Genotypes
- Red numbers are bootstrap scores. Recall that any bootstrap score >= 90% is considered strong. From image attached answer the following: Are most bootstrap scores in your tree >= 90%? Does your tree support the hypothesis that HIV-1 is closely related to chimpanzee SIV (SIV_CPZ)? Does your tree support the hypothesis that HIV-2 is closely related to various non-chimpanzee SIVs?Explain how having a heterozygous genotype for sickle-cell in Malaria stricken areas of Africa is a benefit. v 3 (12pt) Arial TTTT Paragraph v T T, OM HTHL CSS O S Mashups- Path: p ост 28 MacBook Air 80 esc F1 F2 F3 F4 F5 F6 F7 @ #3 $4 & 1 2 3 4 6. 7 8. Q W R Y U A S F J lock C V N control option command エ D N ピNeurospora of genotype a + c are crossed withNeurospora of genotype + b +. (Here, + is shorthandfor the wild-type allele.) The following tetrads areobtained (note that the genotype of the four sporepairs in an ascus are listed, rather than listing alleight spores):a + c a b c + + c + b c a b + a + ca + c a b c a + c a b c a b + a b c+ b + + + + + b + + + + + + c + + ++ b + + + + a b + a + + + + c + b +137 141 26 25 2 3a. In how many cells has meiosis occurred to yieldthese data?b. Give the best genetic map to explain these results.Indicate all relevant genetic distances, both betweengenes and between each gene and the centromere.c. Diagram a meiosis that could give rise to oneof the three tetrads in the class at the far right inthe list
- Tick all the essential steps to demonstrate a genetic linkage between a disease and a molecular marker in humans. identify the alleles of the genetic marker only for diseased individuals in the pedigree enumerate parental type individuals sequence the wild-type and mutant alleles to find the mutation no correct answer calculate a Lod score calculate the recombination frequency between the mutation and the molecular marker identify the alleles of the genetic marker for each individual in the pedigree pedigree analysis cloning the defective gene enumerate recombinant individualsGonorrhea is a sexually transmissible disease (STD) caused by the bacterium Neiserria gonorrhoeae. In the 1940s, penicillin was introduced as an antibiotic to treat gonorrhea. In particular, the drug inhibits the formation of new cell walls in dividing bacterial cells, making new cells vulnerable to the human body's defences. However, a new strain of Neiserria gonorrhoeae was found that is capable of breaking down penicillin, making this strain resistant. The emergence of this new strain has been associated with instances of non-strict compliance of certain patients on the use of penicillin as well as the improper administration of the drug. Based on the information given, formulate a strategy that could help control this new strain.KARYOTYPE #8 ZWK99032 KEY 14 15 17 19 21 22 Y Is this karyotype male or female? What kind of error (if any). Name of syndrome 9. 3. 20 OXEO gerte
- Indicate whether the following sentences is either True or False and CORRECT the wrong sentences MERS can spread by faecal-oral route and/or aerosol droplet transmission Parvoviruses has very small linear dsDNA at 5000 kb and can only replicate when the cell is co-infected with an adenovirus The Ki-67 protein is a cellular marker for proliferation, and during interphase, it can be exclusively detected by immunohistochemistry within the cytoplasm, but it is absent in quiescent cells (G0)The gene known to be mutated in cases of Agammaglobulinemia 2 (which is inherited in an autosomal recessive pattern) is the immunoglobulin lambda like polypeptide 1 (IGLL1 ENSG00000128322). What is known about the gene is recorded here: http://www.ensembl.org/Homo_sapiens/Gene/Summary?g=ENSG00000128322;r=22:23573125-23580302 Please navigate to the link above to answer the following question: Using the left-hand menu to view the sequence for IGLL1, what are the last 12 nucleic acid bases of exon 1?The gene known to be mutated in cases of Agammaglobulinemia 2 (which is inherited in an autosomal recessive pattern) is the immunoglobulin lambda like polypeptide 1 (IGLL1 ENSG00000128322). What is known about the gene is recorded here: http://www.ensembl.org/Homo_sapiens/Gene/Summary?g=ENSG00000128322;r=22:23573125-23580302 Please navigate to the link above and click, 'show transcript table', to answer the following question: What is the size in amino acid residues of the IGLL1 transcript named IGLL1-203? NOTE: Please give your answer as a number, not a word, and do not type the units.