The grain size curves for soils A, B and C isshown. It is required to classify the soilsaccording to the Unified Soils ClassificationSystem. Use the attached Table.SIEVE ANALYSISSieve No.Diam. (mm)Percent PassingSoil ASoil BSoil C3.55.66751009044.7604810075102.000389260200.840328850400.420287530600.2502268251000.1491865162000.07415601045LL20PL

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Answered: The grain size curves for soils A, B…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Percent Passing (by weight) You are provided the mechanical sieve/hydrometer and Atterberg Limit test results for three soils, labeled as Soil #1, Soil #2, and Soil #3. The mechanical sieve results are shown in Figure 1, while Table 2 presents the Atterberg Limit test results. Classify the soils in accordance with the Unified Soil Classification System (USCS) and AASHTO. 100 90 80 60 50 40 30 20 10 0 0.0001 CLAY SIZE Soil #3 Soil #2 Soil #1 0.001 } Soil #1 #2 SILT SIZE #3 0.01 0.1 Grain Size (mm) Figure 1. Mechanical Sieve and Hydrometer Results for Problem #2. 0.075 mm Table 2. Atterberg Limits (ASTM D4318) for Problem #2. LL 68 39 SAND SIZE ΝΑ 1 PL 19 31 ΝΑ GRAVEL 10
The laboratory test results of six soils are given in the following table. Classify the soils by the AASHTO Soil Classification System and give the group indices. Sieve Analysis-Percent Passing Soil Sieve No. C D A в F 4 100 100 95 95 100 100 10 95 80 80 90 94 94 40 82 61 54 79 76 86 200 65 55 8 64 33 76 Liquid limit 42 38 NP* 35 38 52 Plastic limit 26 25 NP 26 25 28 *NP = nonplastic
The grain-size analysis is for a soil is given as follows: Sieve No. Passing Diameter% (mm) 4.75 2.00 0.850 0.425 0.250 0.150 0.075 # 4 #10 #20 # 40 #60 #100 # 200 94 63 21 10 5. 3. Given that the soil is non plastic, classify the soil by using the Unified Soil Classification System. What is the value of the uniformly coefficient Cu. What is the value of the coefficient of gradation Ce What is the value of the sorting coefficient So. O Classify the type of soil
Plz, solve this problem as detail. Geotechnical Engineering-1
Problem 1.1 The results of particle size analyses and, where appropriate, limit tests on samples of four soils are given in Table. Allot group symbols and give main and qualifying terms appropriate for each soil. BS sieve Particle size Percentage smaller Soil I Soil L Soil J Soil K 63 mm 20 mm 100 6.3 mm 94 100 2 mm 69 98 600 mm 32 88 100 212 mm 13 67 95 100 63 mm 2 37 73 99 0.020 mm 22 46 88 0.006 mm 11 25 71 0.002 mm 4 13 58 Liquid limit Plastic limit Non-plastic 32 78 24 31 Particle size distribution curves. Cu & C,. Soil D10 D30 D60 Cu I J Soil I. Soil J. Soil K. Soil L.
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 100 No. 8 2.380 100 No. 10 2.000 95 No. 20 0.840 81 No. 40 0.420 74 No. 60 0.250 69 No. 100 0.150 55 No. 200 0.075 51 Characteristics of No. 40 Fraction LL 48 PL 40 A. A-5(3) B. A-7-5(4) C. None of these. D. A-5(4) E. A-7-6(3)
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Using the Unified Soil Classification System classify the following three soils: Sieve size Soil 1 Soil 2 Soil 3 % finer % finer % finer No.4 99 97 81 No.10 92 90 70 No.40 86 40 49 No.100 78 35 No.200 60 4 32 LL (%) PL (%) 42 40 60 20 30 28 Cu 34 1.8 800 1.6 0.95 0.2 Note: gravel size is defined by particle size between 4.75mm (#4 sieve) and 75mm. Equation of A-line: Pl = 0.73 (LL - 20%).
How to solve 5.6 part A & B
The table shows the laboratory results of the sieve analysis of a soil sample. Which of the following gives the classification of soil according to the Unified Soil Classification System. Sieve Size Diameter Percent Passing, % 4 4.750 94 10 2.000 88 20 0.850 75 40 0.425 52 60 0.250 24 100 0.150 10 200 0.075
The following data is from a sieve analysis, Sieve No. Mass Retained 4 8. 20 16 25 25 33 50 45 80 38 140 20 200 15 Pan 24 Classify the soil by the USDA soil classification system. Attached is a chart to be used.

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