The gas-phase decomposition of ozone is thought to oc- cur by the following two-step mechanism. Step 1: 03(8) = 02(8) + O(g) (fast) Step 2: 0(8) + O,(8) → 202(8) (slow) (a) Write the balanced equation for the overall reaction. (b) Derive the rate law that is consistent with this mecha- nism. (Hint: The product appears in the rate law.) (c) Is O a catalyst or an intermediate? (d) If instead the reaction occurred in a single step, would the rate law change? If so, what would it be?
The gas-phase decomposition of ozone is thought to oc- cur by the following two-step mechanism. Step 1: 03(8) = 02(8) + O(g) (fast) Step 2: 0(8) + O,(8) → 202(8) (slow) (a) Write the balanced equation for the overall reaction. (b) Derive the rate law that is consistent with this mecha- nism. (Hint: The product appears in the rate law.) (c) Is O a catalyst or an intermediate? (d) If instead the reaction occurred in a single step, would the rate law change? If so, what would it be?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The gas-phase decomposition of ozone is thought to oc-
cur by the following two-step mechanism.
Step 1: 03(8)
= 02(8) + O(g) (fast)
Step 2: 0(8) + O,(8) → 202(8) (slow)
(a) Write the balanced equation for the overall reaction.
(b) Derive the rate law that is consistent with this mecha-
nism. (Hint: The product appears in the rate law.) (c) Is O
a catalyst or an intermediate? (d) If instead the reaction
occurred in a single step, would the rate law change? If so,
what would it be?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd280b91d-a314-47b1-827b-f77581cd9f2a%2F87a4ba30-0320-4ad3-87b1-ae83e48ea6a0%2F81lyu9l.png&w=3840&q=75)
Transcribed Image Text:The gas-phase decomposition of ozone is thought to oc-
cur by the following two-step mechanism.
Step 1: 03(8)
= 02(8) + O(g) (fast)
Step 2: 0(8) + O,(8) → 202(8) (slow)
(a) Write the balanced equation for the overall reaction.
(b) Derive the rate law that is consistent with this mecha-
nism. (Hint: The product appears in the rate law.) (c) Is O
a catalyst or an intermediate? (d) If instead the reaction
occurred in a single step, would the rate law change? If so,
what would it be?
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