The free energy change for the following reaction at 25 °C, when [Hg²*] = 1.17 M and [Sn²+] = 7.31×10³ M, is -205 kJ: Hg²*(1.17 M) + Sn(s)→ Hg(1) + Sn²+(7.31×103 M) AG= -205 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction? | forward v

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The free energy change for the following reaction at 25 °C, when [Hg²+]= 1.17 M and [Sn2+1 = 7.31×10-3 M, is -205 kJ:
Hg?+(1.17 M) + Sn(s)→ Hg(1) + Sn²+(7.31×10-3 M) AG= -205 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction? forward v
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [Hg²+]= 1.17 M and [Sn2+1 = 7.31×10-3 M, is -205 kJ: Hg?+(1.17 M) + Sn(s)→ Hg(1) + Sn²+(7.31×10-3 M) AG= -205 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction? forward v
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