The following intermediate tableau for a dual maximum problem was obtained using the simplex method for optimizing a minimum problem. (see image) Perform all the necessary pivot and row operations to obtain the final tableau. Then, using the final tableau, answer the following questions:               The minimum function value is:  The value of  x1 in the minimum problem is :              The value of  x2  in the minimum problem is:

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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The following intermediate tableau for a dual maximum problem was obtained using the simplex method for optimizing a minimum problem. (see image)

Perform all the necessary pivot and row operations to obtain the final tableau. Then, using the final tableau, answer the following questions:              

The minimum function value is: 

The value of  x1 in the minimum problem is :             

The value of  x2  in the minimum problem is: 

Py₁ Y2
0
1
0
0 1
4/3
$1
1
3
1
10
$2
0
3
10
RHS
23 25
1 0-10 2 0 4
Transcribed Image Text:Py₁ Y2 0 1 0 0 1 4/3 $1 1 3 1 10 $2 0 3 10 RHS 23 25 1 0-10 2 0 4
Expert Solution
Step 1: Finding pivot element

Find the most negative value of the last row. Then the corresponding column is pivot column.

Now we will find the minimum ratio.

  1. Pick out each coefficient in the pivot column that is strictly positive (> 0).
  2. Divide each of these coefficients into the right-side entry (RHS) for the same row.
  3. Identify the row that has the smallest of these ratios.
  4. The basic variable for that row is the leaving basic variable, so replace that variable by the entering basic variable in the basic variable column of the next simplext ableau.

Put a box around this row and call it the pivot row. Also call the number that is in bothb oxes the pivot number.

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