Maximize: P = 6x1 - 9x2 Subject to the constraints: 2x13x2 < 6 x1 + x₂ ≤ 20 X1 ≥ 0 x2 > 0

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use the simplex method to solve the following maximum problem: (see image below)

 

### Linear Programming Problem

**Objective:**

Maximize: \( P = 6x_1 - 9x_2 \)

**Subject to the constraints:**

\[
\begin{align*}
2x_1 - 3x_2 &\leq 6 \\
x_1 + x_2 &\leq 20 \\
x_1 &\geq 0 \\
x_2 &\geq 0 \\
\end{align*}
\]

The problem's goal is to find values of \( x_1 \) and \( x_2 \) that maximize the objective function \( P = 6x_1 - 9x_2 \) while satisfying the given constraints. The constraints represent a system of linear inequalities that define a feasible region, which is a polygon in the first quadrant due to the non-negativity constraints \( x_1 \geq 0 \) and \( x_2 \geq 0 \). The solution lies at one of the vertices of this polygon.
Transcribed Image Text:### Linear Programming Problem **Objective:** Maximize: \( P = 6x_1 - 9x_2 \) **Subject to the constraints:** \[ \begin{align*} 2x_1 - 3x_2 &\leq 6 \\ x_1 + x_2 &\leq 20 \\ x_1 &\geq 0 \\ x_2 &\geq 0 \\ \end{align*} \] The problem's goal is to find values of \( x_1 \) and \( x_2 \) that maximize the objective function \( P = 6x_1 - 9x_2 \) while satisfying the given constraints. The constraints represent a system of linear inequalities that define a feasible region, which is a polygon in the first quadrant due to the non-negativity constraints \( x_1 \geq 0 \) and \( x_2 \geq 0 \). The solution lies at one of the vertices of this polygon.
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