The following intermediate tableau for a dual maximum problem was obtained using the simplex method for optimizing a minimum problem. Py₁ 3/2 1 0 0 1 0 2 0 0 0 The minimum function value is: 1 0 -8 -10 6 0 0 12 Perform all the necessary pivot and row operations to obtain the final tableau. Then, using the final tableau, answer the following questions: The value of ₁ in the minimum problem is: The value of ₂ in the minimum problem is: Y3 -1 3 3 The value of 23 in the minimum problem is: 81 82 83 RHS 1 0 0 2 -1 1 0 8 -1 0 1 6

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