The following intermediate tableau for a dual maximum problem was obtained using the simplex method for optimizing a minimum problem. Py₁ 3/2 1 0 0 1 0 2 0 0 0 The minimum function value is: 1 0 -8 -10 6 0 0 12 Perform all the necessary pivot and row operations to obtain the final tableau. Then, using the final tableau, answer the following questions: The value of ₁ in the minimum problem is: The value of ₂ in the minimum problem is: Y3 -1 3 3 The value of 23 in the minimum problem is: 81 82 83 RHS 1 0 0 2 -1 1 0 8 -1 0 1 6
The following intermediate tableau for a dual maximum problem was obtained using the simplex method for optimizing a minimum problem. Py₁ 3/2 1 0 0 1 0 2 0 0 0 The minimum function value is: 1 0 -8 -10 6 0 0 12 Perform all the necessary pivot and row operations to obtain the final tableau. Then, using the final tableau, answer the following questions: The value of ₁ in the minimum problem is: The value of ₂ in the minimum problem is: Y3 -1 3 3 The value of 23 in the minimum problem is: 81 82 83 RHS 1 0 0 2 -1 1 0 8 -1 0 1 6
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:The following intermediate tableau for a dual maximum problem was obtained using the simplex
method for optimizing a minimum problem.
Py₁ 3/2
1
0
0
1
0
2
0
0
0
The value of ₁ in the minimum problem is:
The value of 2 in the minimum problem is:
Y3
-1
The value of 3 in the minimum problem is:
81 82 83 RHS
1 0 0
2
1 0
3 -1
3 -1 0 1
1 0 -8 -10 6 0 0 12
Perform all the necessary pivot and row operations to obtain the final tableau. Then, using the final
tableau, answer the following questions:
The minimum function value is:
8
6
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