**Problem 2: Calibration of a 10mL Pipet**The following values were obtained from the calibration of a 10mL pipet: 10.28, 9.99, 10.12, and 9.63 mL. Calculate the mean value and the standard deviation from the mean.### Steps for Calculation:1. **Calculate the Mean (Average):** - Add all the values together. - Divide by the number of values.2. **Calculate the Standard Deviation:** - Find the difference between each value and the mean. - Square each difference. - Find the average of these squared differences. - Take the square root of this average to get the standard deviation.This problem provides an opportunity to apply statistical methods to real-world data obtained from laboratory calibration procedures. Understanding how to calculate and interpret mean and standard deviation is crucial in assessing the accuracy and precision of laboratory equipment.

The readings given are 1) 10.28 mL 2) 9.99 mL 3) 10.12 mL 4) 9.63 mL The mean value or the average value of the sample data set is given by, => Mean = Sum of readingstotal number of readings = 10.28 + 9.99 + 10.12 + 9.634 = 10.005 mL approx. Hence the mean is 10.005 mL approx. The standard deviation from the mean is given by, => Standard deviation (SD) = ∑i = 1n(xi - mean)2n where n = total number of readings. And xi = value of ith reading. Hence substituting the values we get, => SD = (10.28 - 10.005)2 + (9.99 - 10.005)2 + (10.12 - 10.005)2 + (9.63 - 10.005)24 = 0.240 approx. Hence the standard deviation from mean is 0.240 mL approx.

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The following values were obtained from the calibration of a 10mL pipet 10.28, 9.99, 10.12, and 9.63 mL. Calculate the mean value and the standard deviation from the mean.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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