The following table summarizes data on smoking status and age group, and is consistent with summary quantities obtained in a poll published in a particular article. Smoking Status Age Group Smoker Nonsmoker 18 to 29 174 518 30 to 49 233 1,115 50 to 64 484 1,445 65 and older 211 1,607 Assume that it is reasonable to consider these data as representative of the American adult population. Consider the chance experiment of randomly selecting an adult American. (Round your answers to three decimal places.) (d) What is the probability that the selected adult is a smoker or is age 65 or older?

The following table summarizes data on smoking status and age group, and is consistent with summary quantities obtained in a poll published in a particular article. Smoking Status Age Group Smoker Nonsmoker 18 to 29 174 518 30 to 49 233 1,115 50 to 64 484 1,445 65 and older 211 1,607 Assume that it is reasonable to consider these data as representative of the American adult population. Consider the chance experiment of randomly selecting an adult American. (Round your answers to three decimal places.) (d) What is the probability that the selected adult is a smoker or is age 65 or older?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The following table shows age distribution and location of a random sample of 166 buffalo in a national park. Age Lamar District Nez Perce District Firehole District Row Total Calf 14 14 13 41 Yearling 13 10 10 33 Adult 32 26 34 92 Column Total 59 50 57 166 Use a chi-square test to determine if age distribution and location are independent at the 0.05 level of significance. a)Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.)
..... ..... ..... ..
Hello, Need steps and answers pls. ty;)
The city of Hampton is surveying households to see if the number of cats per household has changed over the past decade. The last known average of cats per household was 1.08. What statistical procedure should you use to analyze these data? O one sample z test Oone sample t test O correlated groups t test O independent groups t test
It is common to think that the more education anindividual receives, the higher the person's income is likely to be. Does this idea translate to states? The following data represent the percentage of the population that has at least a bachelor s degree and the per capita personal income for a random sample of states. Test the claim that states with a higher percentage of the population with at least a bachelor's degree have a higher per capita personal income at the 0.05 level of significance. Data Percentage of Population with atLeast a Bachelor's Degree Per Capita Personal Income (Dollars) State Arkansas 17.4 24,289 California 29.8 33,749 Iowa 24.6 29,043 Louisiana 22.3 26,100 Maine 23.7 28.831 Nebraska 26.8 30,758 Ohio 25.0 29,944 Oregon 26.4 29.340 Texas 24.7 29,372 Source: Statistical Abstract of the United States, 2004
(c) Identify the standardized test statistic. Use technology. z=kjkj (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis, and (e) interpret the decision in the context of the original claim. A. RejectH0. There is sufficient evidence to reject the claim that mean bulb life is at least 743 hours. B. Fail to reject H0. There is sufficient evidence to reject the claim that mean bulb life is at least 743 hours. C. Reject H0. There is not sufficient evidence to reject the claim that mean bulb life is at least 743 hours. D. Fail to reject H0. There is not sufficient evidence to reject the claim that mean bulb life is at least 743 hours.
The following sample data were obtained from three populations that did not follow a normal distribution. Sample 1 se 54 59 Sample 2 Sample 3 39 48 49 49 52 56 41 44 59 47 65 51 57
A governmental agency computed the proportion of violent crimes in the United States in a particular year falling into each of four categories. A simple random sample of 500 violent crimes committed in California during that year were categorized in the same way. The following table presents the results. Category U.S.Proportion CaliforniaFrequency Murder 0.018 4 Forcible Rape 0.07 35 Robbery 0.390 218 Aggravated Assault 0.522 243 Can you conclude that the proportions of crimes in the various categories in California differ from those in the United States as a whole? Use the 0.05 level of significance and the P-value method with the TI-84 Plus calculator. (b) Find the P-value. Round the answer to at least four decimal places.
12. The age of random sample of 40 people who attended a show at the fox. Theater are given below. Find the first, second, and third Quartile 20 26 31 34 39 45 50 62 20 29 31 35 40 47 51 63 23 30 32 35 40 49 51 66 23 30 33 37 40 49 54 69 26 30 34 38 42 49 57 72
A recent national report states the marital status distribution of the male population age 18 or older is as follows: Never Married (31.5%), Married (55.7%), Widowed (2.7%), Divorced (10.1%). The table below shows the results of a random sample of 1620 adult men from California. Test the claim that the distribution from California is as expected at the a = 0.01 significance level. a. Complete the table by filling in the expected frequencies. Round to the nearest whole number: Frequencies of Marital Status Outcome Frequency Expected Frequency Never Married 507 Married 896 Widowed 46 Divorced 171 b. What is the correct statistical test to use? Select an answer c. What are the null and alternative hypotheses? OMarital status and residency are dependent. Marital status and residency are independent. The distribution of marital status in California is the same as it is nationally. OThe distribution of marital status in California is not the same as it is nationally. Marital status and…
Samuel F.B. Morse (1791-1872), the creator of the Morse Code, claimed that 12 % of all letters used in English language were "e"s. Suppose random samples of 196 letters are selected from a book. Use this information to answer question below.
The data below represents yearly car insurance premiums in the US for 18 randomly selected drivers. Assuming the data is normally distributed, test the claim that the average yearly car insurance premium for a person in the US is $1,641 using a level of significance of 5%. 1,653 1,668 1,511 1,634 1,645 1,617 1,557 1,581 1,607 1,614 1,616 1,577 1,639 1,659 1,778 1,672 1,578 1,569 What type of test will be used in this problem? What evidence justifies the use of this test? Check all that apply: The population standard deviation is not known The original population is approximately normal np>5 and nq>5 There are two different samples being compared The sample size is larger than 30 The population standard deviation is known The sample standard deviation is not known Enter the null hypothesis for this test.H0 Enter the alternative hypothesis for this test.H1: Is the original claim located in the null or alternative hypothesis? What is the test…