The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experimental conditions.32.1 30.8 31.1 30.4 31.0 31.9USE SALTThe report states that under these conditions, the maximum allowable stopping distance is 30. A normal probability plot validates the assumption that stopping distance is normally distributed.(a) Does the data suggest that true average stopping distance exceeds this maximum value? Test the appropriate hypotheses using a = 0.01.State the appropriate hypotheses.ⒸHO: H * 30H:μ < 30ⒸHO:μ # 30H₁₂ : μ = 30O Ho: μ = 30H₂:μ> 30Ho: μ = 30H₂:μ # 30Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.)t =P-value =What can you conclude?O Reject the null hypothesis. There is not sufficient evidence to conclude that the true average stopping distance does exceed 30 ft.O Reject the null hypothesis. There is sufficient evidence to conclude that the true average stopping distance does exceed 30 ft.O Do not reject the null hypothesis. There is sufficient evidence to conclude that the true average stopping distance does exceed 30 ft.O Do not reject the null hypothesis. There is not sufficient evidence to conclude that the true average stopping distance does exceed 30 ft.(b) Determine the probability of a type II error when a = 0.01, a = 0.65, and the actual value of μ is 31 (use either statistical software or Table A.17). (Round your answer to three decimal places.)B =Repeat this for u = 32. (Round your answer to three decimal places.)B =(c) Repeat (b) using a = 0.80.Use μ = 31. (Round your answer to three decimal places.)B =Use μ = 32. (Round your answer to three decimal places.)B =Compare to the results of (b).O We saw B increase when o increased.O We saw ß decrease when o increased.(d) What is the smallest sample size necessary to have a = 0.01 and 8 = 0.10 when μ = 31 and σ = 0.65? (Round your answer to the nearest whole number.)

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume that the distributions for the following scenarios are normal. Use the normal standard table to find the following probabilities. Fill in blanks, round z-scores to the nearest hundredth. 1) The average score on a math test is 75 with a standard deviation of 8. What is the probability that a randomly selected test has a score of 90 or higher? P(z > ______) = _________ 2) The life of a gas grill is 3.5 years with a standard deviation 0.35 years. What is the probability that the grill will last less than 3 years? P(z < -1.43) = _________ 3) Ambulance response times average 7.5 minutes with a standard deviation of 2.5. What is the probability that an ambulance will respond within 6 to 8 minutes. P(_____ < z < ______) = 0.3050
clear Al 6.4.9 Assigned Media E Question Help An elevator has a placard stating that the maximum capacity is 1296 lb8 passengers. So, 8 adult male passengers can have a mean weight of up to 1296/8= 162 pounds. If the elevator is loaded with 8 adult male passengers, find the probability that it is overloaded because they have a mean weight greater than 162 lb. (Assume that weights of males are normally distributed with a mean of 164 lb and a standard deviation of 34 lb.) Does this elevator appear to be safe? The probability the elevator is overloaded is (Round to four decimal places as needed.) nt sa bri jon Enter your answer in the answer box and then click Check Answer. 1 part remaining Clear ll Check Answer Convright a2020 Dearson Education inc Allrigars resenved I 2020 Pearsoo EdiIcation LTerms of Use J Privacy Poli L Permiccions L ENG O 4) | 直 0 W
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AA A www-awn.aleks.com Honey Blonde Lace F... Pf iCampus Login Bb Week 11 – MAT3004... A ALEKS - Shasia Gibb... O RANDOM VARIABLES AND DISTRIBU.. Standard normal values: Basic Let z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of c. P(Z>c) = 0.1170 Round your answer to two decimal places. Explanation Check Terms of Use| Privacy Accessibility II
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