The following MINITAB output presents the results of a hypothesis test for a population mean u. Some of the numbers are missing. Fill them in. One-Sample T: X Test of mu = 16 vs not = 16 %3D Variable N Mean StDev SE Mean 95% CI тР х 11 13.2874 (a) 1.8389 ((b), (c)) (d) 0.171
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- Read the problem below and answer the following questions. 1) What statistical test should be used to solve this problem? 2) State the null and alternative hypotheses for the test. Bicep strength (kg/cm2) was measured in 2 groups of 12 males each (age=18-25). One group received a hormone injection (H) and the other did not (NH). Is mean bicep strength greater in the group receiving the hormone injection? For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph Arial 14px A V ...You wish to test the following claim (Ha) at a significance level of a 0.01. Ho:H1 = 42 Ha:H1 > H2 You believe both populations are normally distributed, but you do not know the standard deviations for either. However, you also have no reason to believe the variances of the two populations are not equal. You obtain a sample of size n1 = 25 with a mean of M1 = 52.5 and a standard deviation of SD, = 9.1 from the first population. You obtain a sample of size n2 = 18 with a mean of M2 = 48.7 and a standard deviation of SD2 = 5.2 from the second population. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? For this calculation, use the conservative under-estimate for the degrees of freedom as mentioned in the textbook. (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the…Á study was conducted that examined the relationship between alcohol consumption and risk of heart attack. In all, 417 men, age 40 or older, were tracked over ten years and the number of that experienced a heart attack was recorded. The participants were grouped by those who totally abstained from alcohol and those that drank moderately. For the results given in the table below, use the chi-squared test to find the p value for NHST at the .05 level. (In SPSS use the Yates continuity correction value.) Heart attack Alcohol Crosstabulation Count Alcohol Abstainer Moderate Total Heart attack No 197 192 389 Yes 9. 19 28 Total 206 211 417 Op= .090 Op= 121 !! Op=.067 Op = .048
- The population of healthy female adults, the mean red blood cell count (RBC) is 4.8 (millions of cells per cubic millimeter of whole blood). A researcher thinks the RBC is underestimated, so she conducts a test of significance using Null Hypothesis: µ ≤ 4.8 vs. Alternative Hypothesis: µ >4.8. If the true mean RBC is 4.75 and the null hypothesis is rejected, out of the four options below, what has occured? Type 1 Error, Type 2 Error, No error, OR can’t tell without knowing the degrees of freedom?The null and alternate hypotheses are: He: P₁ =H₂ H₁ H₁ #P₂ A random sample of 15 observations from the first population revealed a sample mean of 350 and a sample standard deviation of 12. A random sample of 17 observations from the second population revealed a sample mean of 342 and a sample standard deviation of 15. The population variances are assumed to be equal. At the 0.10 significance level, is there a difference in the population means? a. Is this a one-tailed or a two-tailed test? O One-tailed test. OTwo-tailed test. b. State the decision rule. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.) The decision rule is to reject H0 if tA consultant for a large university studied the number of hours per week freshmen watch TV versus the number of hours seniors do. The results of this study follow. Is there enough evidence to show the mean number of hours per week freshmen watch TV is different from the mean number of hours seniors do at a=0.1? Freshmen Seniors 4 xbar 18.0 11.0 7.8740 3.9749 For the hypothesis stated above (in terms of Seniors- Freshmen): Question 1 What is/are the critical value(s)? Question 2 What is the decision? Question 3 What is the p-value? Fill in only one of the following statements. Ifthe Z table is appropriate, p-value Ifthet table is appropriate, p-value < <
- You wish to test the following claim (Ha) at a significance level of a = 0.001. H.:µ1 = µ2 Ha:µ1 # µ2 You believe both populations are normally distributed, but you do not know the standard deviations for either. However, you also have no reason to believe the variances of the two populations are not equal (So use the "pool" option). You obtain the following two samples of data. Sample #1 Sample #2 86.4 60.5 63.3 93.5 94.6 61.1 99.2 55.9 85.8 107 88.9 68.8 88.3 61.9 78.8 59.2 103.8 99.7 74.3 72.5 76.5 62 70.5 80.7 80.2 59.2 64.3 107 89.3 113.2 48.5 95.2 72.1 76.1 115.5 75.1 97.6 88.4 96.4 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? For this calculation, use the P-value reported from the "2-sample t- test" from the technology you are using. (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a greater than a This test statistic leads…Professor Nord stated that the mean score on the final exam from all the years he has been teaching is a 79%. Colby was in his most recent class, and his class’s mean score on the final exam was 82%. Colby decided to run a hypothesis test to determine if the mean score of his class was significantly greater than the mean score of the population. α = .01. What is the mean score of the population? What is the mean score of the sample? Is this test one-tailed or two-tailed? Why?Please answer I = 1 II = -2 III = 4
- Consider the information above and in question 1. It is conjectured that the mean number of people attending all 2017 Veterans Day celebrations is 145, and of interest is to test this conjecture versus the alternative that the mean number of people attending all 2017 Veterans Day celebrations is different from 145 people To test the hypothesis, a simple random sample of 41 Veterans Day celebrations was selected and the number of people attending each was recorded. The mean number of people attending for this sample of 41 celebrations was 157, with a standard deviation of 23 people. The distribution of the data was bimodal. If appropriate, use this information to test the hypotheses stated in question 3 at the a = .05 level of significance. O 7 What is the p-value? 0.05 p-value < 0.10 0.0005 0.03 0.001 < p-value < 0.002 0.0008 4-Albumin is a liver protein that helps circulate vitamins throughout the body. Reduced Albumin has been associated with severe illness with Covid-19 patients. Suppose we wanted to conduct a study to compare the mean Albumin concentration (g/L) between a sample of adult patients hospitalized for Covid 19 (Sample Mean= 32.8, s=6.0) to the mean albumin concentration (g/L) of healthy adults (u=34.1, o=7.13). How many patients would need to enroll from the hospital to conduct this study with 99% confidence, and 80% power? A. 267 B. 120 C. 352 D. 225Using a sample that has n=50 pair of data, we get a correlation coefficient r=-0.269 for the following null and alternative hypotheses determine and compute the test statistic value: HO: p=0 H1: pe 0 O a t=7.51 O b. z=7.51 O o.z=-0. 16 Odt=-1.08