### Hypothesis Testing for Veterans Day Celebrations AttendanceConsider the information above and in question 1. It is conjectured that the mean number of people attending all 2017 Veterans Day celebrations is 145, and of interest is to test this conjecture versus the alternative that the mean number of people attending all 2017 Veterans Day celebrations is different from 145 people.To test the hypothesis, a simple random sample of 41 Veterans Day celebrations was selected and the number of people attending each was recorded. The mean number of people attending for this sample of 41 celebrations was 157, with a standard deviation of 23 people. The distribution of the data was bimodal. If appropriate, use this information to test the hypotheses stated in question 3 at the \( \alpha = 0.05 \) level of significance.---### Question 7**What is the p-value?**- 0.05 < p-value < 0.10- 0.0005- 0.03- 0.001 < p-value < 0.002- 0.0008---**Explanation for Educators:**- **Hypothesis testing** is a statistical method used to make decisions about the population parameters based on sample data.- The **null hypothesis (H₀)** is that the mean number of people attending all 2017 Veterans Day celebrations is 145.- The **alternative hypothesis (H₁)** is that the mean number of people attending all 2017 Veterans Day celebrations is different from 145.- A **simple random sample** ensures each celebration has an equal chance of being selected, providing unbiased results.- The **mean (average)** number of people attending this sample is a crucial point in testing our hypothesis.- **Standard deviation** indicates the dispersion of the sample data from the mean.- **Bimodal distribution** suggests two different peaks in the data, which can affect the interpretation.- The **p-value** helps us determine the significance of our results. A lower p-value (< 0.05) indicates strong evidence against the null hypothesis.In this scenario, determining the exact p-value from the choices given is essential to conclude whether to reject the null hypothesis or not.

The question is about hypo. testing Given : Popl. mean no. of people attending Veterans Day…

Answered: Consider the information above and in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Two popular brands of tires for tractor-trailers are the Puma and the Eternal. Salma is a buyer for a major shipping company and wants to determine if there is any difference between the two brands of tire in the mean distance (in thousands of km) driven on them before they need to be replaced. In the company's testing lab, Salma tests a random sample of 14 Puma tires and a random sample of 15 Eternal tires. (These samples are chosen independently.) For the Puma tires, the sample mean distance (in thousands of km) until they would need to be replaced is 54.71 with a sample variance of 5.95. For the Eternal tires, the sample mean distance (in km) until they would need to be replaced is 50.21 with a sample variance of 37.75. Assume that the two populations of distances driven are approximately normally distributed. Can Salma conclude, at the 0.05 level of significance, that there is a difference between the population mean of the distances (in thousands of km) driven on Puma tires before…
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Suppose we measure GPA for people in our class, we find the mean is 2.8 and the median is 3.2. What can you say is most likely true about GPAs in our class?
An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 250 Fundash runners and 285 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 250 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.7 minutes. The 285 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.6 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, u, of Fundash is not equal to the mean completion time, µa, of Coolsprint? Perform a two-tailed test.…
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An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 240 Fundash runners and 200 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 240 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.2 minutes. The 200 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.4 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, μ1 , of Fundash is not equal to the mean completion time, μ2 , of Coolsprint?…
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