2. The following MINITAB output presents the results of a hypothesis test for a population mean µu.One-Sample Z: XTest of mu =The assumed standard deviation73.5 vs not = 73.52.3634=VariableNMean73.2461StDev2.3634SE Mean95% CIZ0.1961450.1963(72.8614, 73.6308)-1.29a. Is this a one-tailed or two-tailed test?b. What is the null hypothesis?с.What is the P-value?

For the given MINITAB output Answer all the questions

Answered: 2. The following MINITAB output…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A textile fiber manufacturer is investigating a new drapery yam, which the company claims has a mean thread elongation of 12 kilograms with a standard deviation of 0.5 kilograms. The company wishes to test the hypothesis using a random sample of four specimens. Identify the appropriate hypotheses test. a. Test on Mean, Variance Known b. Test on Variance and Standard Deviation c. Test on Population Proportion d. Test on Mean, Variance Unknown
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1. Depression scores (1-100) for young women (20-40 years old) are assumed to be normally distributed with a mean of 75.5 within the population. A sample of 26 women were recruited to have their depression scores recorded and the mean score was 82, with a standard deviation of 12. Researchers want to know if the sample data reflects a population with mean score of 75.5. Using a significance level of 0.01, answer the following questions. (a) What statistical test should the researchers conduct? Why? Explain your answer. (b) State the hypotheses for this scenario. (c) Conduct a hypothesis test based on question 1(a) to determine what the researcher should conclude from this study. Give your answer to two decimal places. (d) Suppose you obtained several random samples each with n = 100 women and each time you obtained their depression scores. Is it reasonable to assume that the sample means of these samples xx are approximately Normally distributed even though the population distribution…
Sixty gym members were randomly selected and their weights were recorded and inputted into MINITAB. The results are summarized in Exhibit 1 below. One-Sample Z: Weight Test of mu = 195 vs < 195 The assumed standard deviation = 22.11 Variable = N Weight = 60 Mean = 193.13 Standard Deviation =22.11 SE Mean = *What is the value of test statistic for this test.?
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