The following formula gives the distance between two points (x1, y1) and (x2, y2) in the Cartesian plane: Note that thecalculation of the radius of a circle is a specialized version of the distance calculation. For this program write a function called calcDistance with the precondition that it takes as input the coordinates of two points on the cartesian plane and the postcondition that it returns the distance between these two points. The write a function called calcRadius with the precondition that it takes as input the coordinates for the center of a circle and the coordinates of a point on the circumference. The postcondition is that it returns the radius of the circle. Have the specialized calcRadius function call the more general calcDistance function which would return the result of the distance function as the radius of the circle. Notice that the output for the program does not ask for the distance, it only asks for the radius so the calcDistance function is "hidden" from the main function. Include a function calcCircumference which takes as input the radius of the circle and returns the circumference (If ris the radius, the circumference is 2nr). Also include a function calcArea which takes as input the radius of the circle and returns the area (if ris the radius, the area is Tr2). Assume that n=3.1416. Consider the main function for this program to be an application.Provide comments at the beginning of the program that describe the user input, the processing, and the output the program will produce (i.e., your IPO chart in comment form). The processing may be described as an algorithm, you do not have to provide pseudocode. Use prototypes for your functions and document the preconditions and postconditions for your functions as comments before or after the prototype.Put the function definitions after the main function. √(x₂ − x1)² + (Y2 — Y₁)²
The following formula gives the distance between two points (x1, y1) and (x2, y2) in the Cartesian plane: Note that thecalculation of the radius of a circle is a specialized version of the distance calculation. For this program write a function called calcDistance with the precondition that it takes as input the coordinates of two points on the cartesian plane and the postcondition that it returns the distance between these two points. The write a function called calcRadius with the precondition that it takes as input the coordinates for the center of a circle and the coordinates of a point on the circumference. The postcondition is that it returns the radius of the circle. Have the specialized calcRadius function call the more general calcDistance function which would return the result of the distance function as the radius of the circle. Notice that the output for the program does not ask for the distance, it only asks for the radius so the calcDistance function is "hidden" from the main function. Include a function calcCircumference which takes as input the radius of the circle and returns the circumference (If ris the radius, the circumference is 2nr). Also include a function calcArea which takes as input the radius of the circle and returns the area (if ris the radius, the area is Tr2). Assume that n=3.1416. Consider the main function for this program to be an application.Provide comments at the beginning of the program that describe the user input, the processing, and the output the program will produce (i.e., your IPO chart in comment form). The processing may be described as an algorithm, you do not have to provide pseudocode. Use prototypes for your functions and document the preconditions and postconditions for your functions as comments before or after the prototype.Put the function definitions after the main function. √(x₂ − x1)² + (Y2 — Y₁)²
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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