The following figure shows a sequential circuit with one D Flip Flop with a common input clock (C). Assume that the flip flop is initialized at ‘0’. That is, Z = 0 during Cycle 0. This means the output of this circuit is initially 0. Compute the value of the output signal (Z) for 10 cycles using the table below.
The following figure shows a sequential circuit with one D Flip Flop with a common input clock (C). Assume that the flip flop is initialized at ‘0’. That is, Z = 0 during Cycle 0. This means the output of this circuit is initially 0. Compute the value of the output signal (Z) for 10 cycles using the table below.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
The following figure shows a sequential circuit with one D Flip Flop with a
common input clock (C). Assume that the flip flop is initialized at ‘0’. That is, Z = 0 during Cycle 0. This means the output of this circuit is initially 0. Compute the value of the output signal (Z) for 10 cycles using the table below.
![### Diagram Description
The image shows a digital circuit schematic consisting of an AND gate connected to a D-type flip-flop. The inputs to the AND gate are labeled as A and B, while the output of the AND gate is connected to the data input (D) of the flip-flop. The flip-flop's clock input is labeled as C, and the output is labeled as Z. The output Z is also fed back to the D input, indicating a feedback loop setup in the circuit.
### Truth Table
Below is the truth table that represents the behavior of the circuit over several clock cycles:
| Clock Cycle (C) | A | B | Z |
|-----------------|---|---|---|
| 0 | 0 | 1 | 0 |
| 1 | 1 | 1 | 1 |
| 2 | 1 | 0 | 0 |
| 3 | 1 | 0 | 0 |
| 4 | 0 | 0 | 0 |
| 5 | 0 | 0 | 0 |
| 6 | 1 | 1 | 1 |
| 7 | 0 | 1 | 0 |
| 8 | 0 | 1 | 0 |
| 9 | 1 | 1 | 0 |
| 10 | 0 | 0 | 0 |
### Explanation
- **Clock Cycle 0:** With A = 0 and B = 1, the output Z is 0 because the AND gate requires both A and B to be 1 to produce a 1.
- **Clock Cycle 1:** With A = 1 and B = 1, the output Z becomes 1 as both inputs to the AND gate are 1.
- **Clock Cycles 2-10:** The value of Z depends on the current inputs A and B as well as the feedback loop established through the flip-flop, causing the circuit to exhibit state-dependent behavior typical of sequential logic circuits.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff4f8485b-d935-478d-91e7-b806502d9702%2F3f5a4b0e-6fdb-457b-a662-e761f21efbba%2F02dljoc_processed.png&w=3840&q=75)
Transcribed Image Text:### Diagram Description
The image shows a digital circuit schematic consisting of an AND gate connected to a D-type flip-flop. The inputs to the AND gate are labeled as A and B, while the output of the AND gate is connected to the data input (D) of the flip-flop. The flip-flop's clock input is labeled as C, and the output is labeled as Z. The output Z is also fed back to the D input, indicating a feedback loop setup in the circuit.
### Truth Table
Below is the truth table that represents the behavior of the circuit over several clock cycles:
| Clock Cycle (C) | A | B | Z |
|-----------------|---|---|---|
| 0 | 0 | 1 | 0 |
| 1 | 1 | 1 | 1 |
| 2 | 1 | 0 | 0 |
| 3 | 1 | 0 | 0 |
| 4 | 0 | 0 | 0 |
| 5 | 0 | 0 | 0 |
| 6 | 1 | 1 | 1 |
| 7 | 0 | 1 | 0 |
| 8 | 0 | 1 | 0 |
| 9 | 1 | 1 | 0 |
| 10 | 0 | 0 | 0 |
### Explanation
- **Clock Cycle 0:** With A = 0 and B = 1, the output Z is 0 because the AND gate requires both A and B to be 1 to produce a 1.
- **Clock Cycle 1:** With A = 1 and B = 1, the output Z becomes 1 as both inputs to the AND gate are 1.
- **Clock Cycles 2-10:** The value of Z depends on the current inputs A and B as well as the feedback loop established through the flip-flop, causing the circuit to exhibit state-dependent behavior typical of sequential logic circuits.
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