The following data was obtained from standard proctorcompaction test:Weight of Weight of mold+ Weight ofmold+ base compacted moistplate,w1, (gMoist Moisture Dry unitunitTestNo.moistcontent,weight,soil+ base plate, compacted weight,W2, (g)We(%)soil,(g/cm3)Ymoist(g/cm3)W2-W1,(g)1157802070015780211603157802130015780213601578021400Water content determination:wi(mass ofempty can)W2(mass of can+moist soil)W3(mass ofcan+ dry soil)Test No.Watercontent(W%)1.15.3473.1871.062.15.3484.4580.52312.6659.5856.64416.8488.9183.6112.6698.190.33Volume of mold = 944cm3Calculate the maximum dry unit weight and O.M.C (show all your calculations anddrawing)

Answered: Image /qna-images/answer/5c8dadec-38d5-497a-bf00-3636a5551806.jpg

The following data was obtained from standard proctor compaction test: Weight of Weight of mold+ Weight of mold+ base Moist Moisture Dry unit content, weight, We(%) Test moist compacted moist soil+ base plate, compacted weight, W2, (g) No. unit plate, w1, (g ydry (g/cm3) soil, Ymoist (g/cm3) W2-W1, (g) 1. 15780 20700 2. 15780 21160 15780 21300 4 15780 21360 15780 21400 Water content determination: wi(mass of empty can) W2(mass of can+ moist soil) Wa(mass of can+ dry soil) Test No. Water content (W%) 1. 15.34 73.18 71.06 2 15.34 84.45 80.52 12.66 59.58 56.64 4 16.84 88.91 83.61 12.66 98.1 90.33 Volume of mold = 944cm3 Calculate the maximum dry unit weight and O.M.C (show all your calculations and drawing)

The following data was obtained from standard proctor compaction test: Weight of Weight of mold+ Weight of mold+ base Moist Moisture Dry unit content, weight, We(%) Test moist compacted moist soil+ base plate, compacted weight, W2, (g) No. unit plate, w1, (g ydry (g/cm3) soil, Ymoist (g/cm3) W2-W1, (g) 1. 15780 20700 2. 15780 21160 15780 21300 4 15780 21360 15780 21400 Water content determination: wi(mass of empty can) W2(mass of can+ moist soil) Wa(mass of can+ dry soil) Test No. Water content (W%) 1. 15.34 73.18 71.06 2 15.34 84.45 80.52 12.66 59.58 56.64 4 16.84 88.91 83.61 12.66 98.1 90.33 Volume of mold = 944cm3 Calculate the maximum dry unit weight and O.M.C (show all your calculations and drawing)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Show solution for prob 7
The table below shows the results of CU test for a soil sample (h=76 mm, and D= 38 mm), Find the X value, if you know the decrease in VO=2.5 % in consolidation stage. Shearing stage (ho=75 mm) Axial dial gauge reading (F=0.01 mm/div.) Corrected area mm 30 75 120 no one O 1133 mm2 1105 mm2 O 1110 mm2 O 1176 mm2
6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water content and maximum dry unit weight. Determine also the amount of energy expended in the compaction of one of the trials assuming that the test done is standard proctor test. Proctor Mold Volume Mass of wet soil in the Moisture Content Trial (cm³) mold (kG) (%) 1 943.3 1.68 9.9 943.3 1.71 10.6 3 943.3 1.77 12.1 4 943.3 1,83 13.8 943.3 1.86 15.1 6 943.3 1.88 17.4 943.3 1.87 19.4 8 943.3 1.85 21.2
please solve question 4, 5 and 6
1. Estimate soil porosity where particle and bulk den- sities were, respectively, 2.6 g/cm³ and 1.7 g/cm³ (a) 1.53 (Ъ) 0.35 (c) 0.65 (d) 0.53 (e) 1.35
SG is 2.66 and temperature is 18 degrees celcius
Show solution for prob 4
1.5 cm datum The following are the results of a compaction test; Mass of mold+wet soil(g) 2925 3095 3150 3125 3070 Water content% 10 12 14.3 16.1 18.2 If the volume of mold = 1000 ml, and mass of mold = 1000 g, and Specific gravit of solids = 2.70. G4 Wc a. Find the compaction curve showing the optimum moisture content and maximu dry density. b. Plot the zero air void line. c. Determine the degree of saturation at the maximum dry density. Sr P COONCOM
A compaction test was conducted in a soils laboratory using the Standard Proctor Method B test procedure. The weight of the compact soil specimen plus mold and baseplate was determined to be 3841 g. The volume and mass of the mold were 943.7 cm³ and 2066.0 g, respectively. A moisture content test was carried out on a representative portion of the sample and the results were 9.8%. Required Determine the dry unit weight in metric units, to the nearest 100th. Your Answer:
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For a soil specimen, given the following: % passing sieve #4-92 %, sieve #10 -81%, sieve # 40-78%, LL-48%, PL-16%, GI-18.2 classify the soil by AASHTO classification system. GI = (F200-35)[0.2 + 0.005 (LL - 40)] +0.01 (F20015)(PI – 10)
Please kindly answer all. C and d answers mandatory. Please answer all and help me.. thank you