6. The results of a standard Proctor Test are tabulated as follows.Volume of Proctor Mold(ft³)Weight of Wet Soil in Mold(lb) Moisture Content(w%)1/303.69121/303.62141/303.88161/303.87181/303.87201/303.7721a. Determine the moist unit weight (ymoist) and dry unit weight (yd). Plot the value of dry unitunit weight (yd) versus the value of moisture content (w%) and estimate the maximum dryunit weight (ydmax) and the corresponding optimum moisture content (w%)b. Determine the void ratio at the optimum moisture content if G s = 2.68c. Determine the degree of saturation at the optimum moisture content.Use the graph form below for plotting the compaction curve.COMPACTION CURVED 20.5R 20Y 19.5U 18918| 17.5T 16.3W1615.515 7 9 11 13 151719 212325 27293133 35 37 39GMoisture Content (w%)T (KN/m^3)

a) Calculate the bulk density ,moist unit weight and dry density as given as , Bulk density =weight…

6. The results of a standard Proctor Test are tabulated as follows. Volume of Proctor Mold(ft³) Weight of Wet Soil in Mold(lb) Moisture Content(w%) 1/30 3.69 12 1/30 3.62 14 1/30 3.88 16 1/30 3.87 18 1/30 3.87 20 1/30 3.77 21 a. Determine the moist unit weight (ymoist) and dry unit weight (yd). Plot the value of dry unit

6. The results of a standard Proctor Test are tabulated as follows. Volume of Proctor Mold(ft³) Weight of Wet Soil in Mold(lb) Moisture Content(w%) 1/30 3.69 12 1/30 3.62 14 1/30 3.88 16 1/30 3.87 18 1/30 3.87 20 1/30 3.77 21 a. Determine the moist unit weight (ymoist) and dry unit weight (yd). Plot the value of dry unit

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter6: Soil Compaction

Section: Chapter Questions

Problem 6.9P

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The laboratory test data for a standard Proctor test are given below. Find the maximum dry unit density and optimum moisture content.
Problem (6) The laboratory test data for a standard Proctor test are given below. Volume of Proctor mold Mass of wet soil in the mold (kg) Moisture conient (%) (ст3) 943.3 943.3 1.65 10 1.75 12 943.3 1.83 1.81 14 943.3 16 943.3 1.76 18 943.3 1.70 20 a) Find the maximum dry unit weight and optimum moisture content. b) Calculate the zero-air-void unit weights for a soil with G, =2.68 at moisture content of 5, 10, 15, 20, and 25%. Plot a graph of Yrav versus moisture content.
The results of a Standard Proctor test are given in the following table. Moist Weight of Wet Sol Moisture Content in the mold (Ib) Trial (%) 26 4.08 28 4.12 30 4 4,18 32 Determine: 1. Maximum dry unit weight in Ib/ft^3 (4 decimal places) 2. Optimum water content in % (4 decimal places)
The results of a standard Proctor Test are tabulated as follows. Volume of Proctor Mold(ft³) Weight of Wet Soil in Mold(lb) Moisture Content(w%) 1/30 3.69 12 1/30 3.62 14 1/30 3.88 16 1/30 3.87 18 1/30 3.87 20 1/30 3.77 21 . a. Determine the moist unit weight (ymoist) and dry unit weight (yd). Plot the value of dry unit unit weight (yd) versus the value of moisture content (w%) and estimate the maximum dry unit weight (ydmax) and the corresponding optimum moisture content (w%) b. Determine the void ratio at the optimum moisture content if G s = 2.68 c. Determine the degree of saturation at the optimum moisture content. Use the graph form below for plotting the compaction curve. COMPACTION CURVE D 20.5 R 20 Y 19.5 U 189 N 18 17.5 T 1613 W 16 E 15.5 15 7 9 11 13 151719 212325 27293133 35 37 39 Moisture Content (w%) H T (KN/m^3)
Hi, pls help me answer this one. I need it asap. Thank you.
A Standard Proctor test has yielded the values shown below. Determine the maximum dry unit weight and its OMC; remember V = 1/30 ft3. No Weight of wet soil (lb) Moisture % 1 3.26 8.24 4.15 10.20 4.67 12.30 4 4.02 14.60 3.36 16.80 2.
Answer in three decimal places please
2. The results of the standard proctor test are given in the following table. Test Number Volume of Proctor Moist Weight of Wet Soil in the mold(kg) Moisture Content Mold (cm³) w% 1 943.3 1.68 9.9 943.3 1.71 10.6 3 943.3 1.77 12.1 4 943.3 1.83 13.8 943.3 1.86 15.1 6 943.3 1.88 17.4 7 943.3 1.87 19.4 943.3 1.85 21.2 Determine the following: Note: Plot moisture content versus dry unit weight. a. The maximum dry unit weight of compaction. b. The optimum moisture content. c. The moisture content to achieve 95% of ydmax
Please answer situation 4
Can you please only answer B & C. Show clear work please so I can understand the concept!
1. The following data shows the results of the liquid limit and plastic limit test using Casagrande cup method. Calculate the following: (Hint: Solve the moisture content of each test) a. Liquid Limit b. Plasticity Index c. Liquidity Index Liquid Limit Test: TEST NO. No. of Blows Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container Plastic Limit Test: TEST NO. Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container Natural Water Content: TEST NO. Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container 1 35 22.46 g 19.44 g 12.76 g 1 22.10 g 20.42 g 13.07 g 1 17.94 g 14.84 g 7.84 g 2 21 21.33 g 18.75 g 13.06 g 2 21.77 g 20.19 g 13.28 g 2 17.39 g 14.36 g 7.50 g 3 16 21.29 g 18.78 g 13.26 g
Problem A liquid limit test conducted on a soil sample in the cup device gave the following results: N 10 19 23 27 40 w (%) 60.0 45.3 39.8 36.5 25.2 The plastic limit test and natural water content. Plastic Limit Natural Water Content Test Test No. Weight of Container + Lid (g) 2 1 2 13.07 13.18 7.84 7.5 Weight of Container + Lid + Wet Soil (g) 22.12 21.84 17.53 16.97 Weight of Container + Lid + Dry Soil (g) 20.59 20.35 15.45 14.93 The shrinkage limit test. Weight of Dish with petroleum jelly (g) Weight of Dish with petroleum jelly+ Wet Soil (g) Weight of Dish with petroleum jely + Dry Soil (g) Volume of Shrinkage Dish (cm³) Volume of Oven-Dried Soil Pat (cm?) 11.3 38.51 32.81 15.26 12.83 8. Determine the liquid limit. b. 39% 9. Determine the plastic limit. a. 38% C. 37% d. 40% b. 21.20% 10. Determine the shrinkage limit. 20.55% C. 21.85% d. 20.20% a. a. 15.20% b. 22.40% C. 18.59% d. 16.45%