The following code is supposed to return nl, for positive n. An analysis of the code using our Three Question" approach reveals that:int factorial(int n)£if (n -- e)return 1;elsereturn (n - factoriel(n - 1));it fails the smaller-caller question.it fails the general-case question.it passes on all three questions and is a valid algorithm.it fails the base-case question.

Objective: A recursive algorithm for computing the factorial of a value is stated. We need to check…

Answered: The following code is supposed to…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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A palindrome is a string that reads the same forward and backward. For example,“deed” and “level” are palindromes. Write an algorithm in pseudocode that testswhether a string is a palindrome. Implement your algorithm as a static method inJava. The method should call itself recursively and determine if the string is apalindrome.Write a main method that reads a string from the user as input and pass it to thestatic method. You need to validate the string and make sure it contains only letters(no digits or special characters are allowed). The main method should displaywhether the string is a palindrome or not. a) Read the string from the user and validate it.b) Create a method that calls itself recursively and returns whether thestring is a palindrome or not.c) Include a test table with at least the following test cases:1. Invalid input. For example, string contains a number or specialcharacter.2. A valid string that is a palindrome.3. A valid string that is not a palindrome.
Which among the following is the recursive definition of Factorial , i.e., n! ? f(0) = 1, f(n) = (n)f(n – 1), where n E Z andn 2 1. %D f(0) = 1, f (n) = (n + 1)f(n – 1), where n E Z and n > 1. f(0) = 0, f(n) = (n)f(n – 1), where n E Z and n > 1. %3D f (0) = 0, f(n) = (n + 1)f(n – 1), where n E Z and n 2 1.
Given an input string, a non-empty substring subs, and a non-negative number n, compute recursively and return true if and only if at least n copies of subs occur in the string, possibly with overlapping. Do not use loops (do not write for or while anywhere in your code). Do not use any regular expressions and methods such as matches, split, replaceAll. Test case 1: checkSubstring("abcxxxxabc", "abc", 2) true Test case 2: checkSubstring("abcxxxxabc", "abc", 3) false Test case 3: checkSubstring ("ababaxxxaba", "aba", 3) true

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