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else C. return (base * } b. int factorial (int n) ( if (n > 0) return (n* factorial (n-1)); else if (n == 0) return 1; } int recur (int n) { if (n < 0) return -1; else if (n < 10) return 1; else power (base, exponent - 1)); return (1 + recur (n / 10)); } d. int recur2 (int n) { if (n < 0) return -1; else if (n < 10) return n; else w od bluow taning tuo. _*((80) )4[28131;389;" bortem guiwol (0 return ((n % 10) + recur2 (n / 10)); house

else C. return (base * } b. int factorial (int n) ( if (n > 0) return (n* factorial (n-1)); else if (n == 0) return 1; } int recur (int n) { if (n < 0) return -1; else if (n < 10) return 1; else power (base, exponent - 1)); return (1 + recur (n / 10)); } d. int recur2 (int n) { if (n < 0) return -1; else if (n < 10) return n; else w od bluow taning tuo. _*((80) )4[28131;389;" bortem guiwol (0 return ((n % 10) + recur2 (n / 10)); house

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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For each of the following recursive methods, identify the base case, the general case, and the constraints on the argument values, and explain what the method does. (images below) 

the general case, and the constraints on the argument values, and explain what the method does. 7. For each of the following recursive methods, identify the base case, t int power (int base, int exponent) { if (exponent return 1; 0)
Transcribed Image Text:the general case, and the constraints on the argument values, and explain what the method does. 7. For each of the following recursive methods, identify the base case, t int power (int base, int exponent) { if (exponent return 1; 0)
Chapter 3 Recurs else return (base* power (base, exponent-1)); } b. int factorial (int n) { if (n > 0) return (n* factorial (n - 1)); else if (n == 0) return 1; } c. int recur (int n) { if (n < 0) return -1; else if (n < 10) return 1; else return (1 + recur (n / 10)); } d. int recur2 (int n) { if (n < 0) return -1; else if (n < 10) return n; else od bluow take pakaq.300.msday 11 APR 20 bodem galwoilot ad (mun sal) 18 return ((n % 10) + recur2 (n / 10)); Mun
Transcribed Image Text:Chapter 3 Recurs else return (base* power (base, exponent-1)); } b. int factorial (int n) { if (n > 0) return (n* factorial (n - 1)); else if (n == 0) return 1; } c. int recur (int n) { if (n < 0) return -1; else if (n < 10) return 1; else return (1 + recur (n / 10)); } d. int recur2 (int n) { if (n < 0) return -1; else if (n < 10) return n; else od bluow take pakaq.300.msday 11 APR 20 bodem galwoilot ad (mun sal) 18 return ((n % 10) + recur2 (n / 10)); Mun
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