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- Lab Goal : This lab was designed to teach you more about recursion. Lab Description : luckyThrees will return a count of the 3s in the number unless the 3 is at the start. A 3 at the start of the number does not count. /* luckyThrees will return the count of 3s in the number* unless the 3 is at the front and then it does not count* 3 would return 0* 31332 would return 2* 134523 would return 2* 3113 would return 1* 13331 would return 3* 777337777 would return 2* the solution to this problem must use recursion*/public static int luckyThrees( long number ){} Sample Data : 331332134523311313331777337777 Sample Output : 0221321. Write a recursive method expFive(n) to compute y=5^n. For instance, if n is 0, y is 1. If n is 3, then y is 125. If n is 4, then y is 625. The recursive method cannot have loops. Then write a testing program to call the recursive method. If you run your program, the results should look like this: > run RecExpTest Enter a number: 3 125 >run RecExpTest Enter a number: 3125 2. For two integers m and n, their GCD(Greatest Common Divisor) can be computed by a recursive function. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Once m is 0, the function returns n. Once n is 0, the function returns m. If neither is 0, the function can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n. Although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. Meaning your code needs to follow the given algorithm. Then…The following recursive method get Number Equal searches the array x of 'n integers for occurrences of the integer val. It returns the number of integers in x that are equal to val. For example, if x contains the 9 integers 1, 2, 4, 4, 5, 6, 7, 8, and 9, then getNumberEqual(x, 9, 4) returns the value 2 because 4 occurs twice in x. public static int getNumberEqual(int x[], int n, int val) { if (n< 0) ( return 0; } else { if (x[n-1) == val) { return getNumberEqual(x, n-1, val) +1; } else { return getNumber Equal(x, n-1, val); } // end if ) // end if } // end get Number Equal Demonstrate that this method is recursive by listing the criteria of a recursive solution and stating how the method meets each criterion.
- Recursive Power MethodWrite a method called powCal that uses recursion to raise a number to a power. The method should accept two arguments: The first argument is the exponent and the second argument is the number to be raised (example” powCal(10,2) means 210). Assume that the exponent is a nonnegative integer. Demonstrate the method in a program called Recursive (This means that you need to write a program that has at least two methods: main and powCal. The powCal method is where you implement the requirements above and the main method is where you make a method call to demonstrate how your powCal method work).Knight's Tour: The Knight's Tour is a mathematical problem involving a knight on a chessboard. The knight is placed on the empty board and, moving according to the rules of chess, must visit each square exactly once. There are several billion solutions to the problem, of which about 122,000,000 have the knight finishing on the same square on which it begins. When this occurs the tour is said to be closed. Your assignment is to write a program that gives a solution to the Knight's Tour problem recursively. You must hand in a solution in C++ AND Java. The name of the C++ file should be "main.cc" and the name of the Java file should be "Main.java". Write C++ only with a file name of main.cc Please run in IDE and check to ensure that there are no errors occuring Output should look similar to: 1 34 3 18 49 32 13 16 4 19 56 33 14 17 50 31 57 2 35 48 55 52 15 12 20 5 60 53 36 47 30 51 41 58 37 46 61 54 11 26 6 21 42 59 38 27 64 29 43 40 23 8 45 62 25 10 22 7 44 39 24 9 28 63please code in python You place a pawn at the top left corner of an n-by-n chess board, labeled (0,0). For each move, you have a choice: move the pawn down a single space, or move the pawn down one space and right one space. That is, if the pawn is at position (i,j), you can move the pawn to (i+1,j) or (i+1, j+1). Ask the user for the size of a chessboard, n (integer). Find the number of different paths starting from (0,0) that the pawn could take to reach each position on the chess board. For example, there are two different paths the pawn can take to reach (2,1). Look at the diagrams below to convince yourself of this. You can see the four paths that you can take by move 2. Start -> Move 1 -> Move 2 (0,0) -> (1,0) -> (2,1) (0,0) -> (1,0) -> (2,0) (0,0) -> (1,1) -> (2,1) (0,0) -> (1,1) -> (2,2) Print the board with the number of ways to reach each square labeled as shown below. For example: Enter a board size: 4 1 0 0 0 1 1 0 0 1 2 1 0 1 3 3 1
- Lab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a number and recursively determine how many of its digits are even. Return the count of the even digits in each number. % might prove useful to take the number apart digit by digit Sample Data : 453211145322224532714246813579 Sample Output : 23540CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021PLEASE answer ASAP I will give upvotes if you answer as soon as possible This is Iterative Improvement
- Java source code writing - a recursive algorithm. Please use non-recursive and recursive ways to determine if a string s is a palindrome, that is, it is equal to its reverse. Examples of palindromes include 'racecar' and 'gohangasalamiimalasagnahog'. Turn in your java source code file with three methods, including one main() method.Please explain the questions related to the code below: //1. Why is 20 printed 3 times and why does it start with 1, but end with 2? //2. What is the base case for this recursive method and why? //3. How would you implement this using a loop? //4. What is each if statement checking? //5. Would a solution to this using loops require more or less code and would it be more or less effecient? //6. Why is recursion a good choice to solve this problem? //7. How can recursion become infinite? //8. When is recursion appropriate? /* Load the code below into a cloud compiler and run each method one at a time by removing the comments for the method. Walk through the code as a group and explore how the code works. Submit the answers to the numbered questions for credit. */ public class DemoRecur { //Simple statement designed to show control flow in recursion public static void printDemo(int x, int max) {…Write a recursive method to determine whether a String contains a 'q' not immediately followed by a 'u' (ignoring capitalization). In other words: • the word does contain at least one 'q' • and that q is followed by anything except a 'u' Carefully review the provided driver program to see example test cases. The method header is: public static boolean qNotFollowedByU(String word)