I'm a bit stuck here. I'm using the OZ language.   Write a non higher order function which computes the Gauss sum, namely 1+2+...+n, where n > 0.   Any help with this is appreciated! Again, I'm using the OZ language.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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I'm a bit stuck here. I'm using the OZ language.

 

Write a non higher order function which computes the Gauss sum, namely 1+2+...+n, where n > 0.

 

Any help with this is appreciated! Again, I'm using the OZ language.

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This was very clearly pulled from Chegg. This was not helpful as the output didn't work in that regard.

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fun {GaussSum N}
if N == 1 then 1 else N+{GaussSum N-1} end
end
Above given function recursively calls itself with the value less than passed value and add the passed
value to its result. It stops when the passing value becomes 1.
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Transcribed Image Text:Expert Answer Anonymous answered this 272 answers fun {GaussSum N} if N == 1 then 1 else N+{GaussSum N-1} end end Above given function recursively calls itself with the value less than passed value and add the passed value to its result. It stops when the passing value becomes 1. Was this answer helpful? B4 80% (5 ratings) 1
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Follow-up Question

That answer was pulled from Chegg..

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Anonymous answered this
272 answers
fun {GaussSum N}
if N == 1 then 1 else N+{GaussSum N-1} end
end
Above given function recursively calls itself with the value less than passed value and add the passed
value to its result. It stops when the passing value becomes 1.
Was this answer helpful?
B4
80% (5 ratings)
1
Transcribed Image Text:Expert Answer Anonymous answered this 272 answers fun {GaussSum N} if N == 1 then 1 else N+{GaussSum N-1} end end Above given function recursively calls itself with the value less than passed value and add the passed value to its result. It stops when the passing value becomes 1. Was this answer helpful? B4 80% (5 ratings) 1
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