The following ciphertext was incrypted in two-letter blocks using RSA with modulus n =4747 and encryption exponent e = 3067. (Note that space is 27)1563 4362 2416 1730 3660 192(a) Find the decryption exponent d.(b) Decrypt the message
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The following ciphertext was incrypted in two-letter blocks using RSA with modulus n =
4747 and encryption exponent e = 3067. (Note that space is 27)
1563 4362 2416 1730 3660 192
(a) Find the decryption exponent d.
(b) Decrypt the message
Step by step
Solved in 2 steps
- Decode the number using the given private key. Decode the number M = 38 using the private key d = 17 and n = 77. Assume you are decoding the number using the RSA cryptosystem. Note: You can use the Modular Exponentiation calculator to help with the calculation.DONT USE AI, USE PENCIL AND PAPER WHILE DOING IT. SHOW ANSWER AND RESULTS An RSA cipher has public key pq = 65 and e = 7. (a) Translate the message YES into its numeric equivalent, and use the formula C = Me (mod pq) to encrypt the message.Decode the number using the given private key. Decode the number M - 15 using the private key d = 53 and n = 77. Assume you are decoding the number using the RSA cryptosystem Note: You can use the Modular Exponentiation calculator to help with the calculation.
- Use the values below to encrypt the numerical message m = 55. Use the following cryptoscheme: Encryption (m + k) mod N = c Decryption (c - k) mod N = m N = 66 K = 20 Example:5Encrypt the message " MATH " by translating the letters into numbers and then applying the encryption function given, and then translating the numbers II back into letters. (a) f(p) = (17p+ 3) mod 26 (b) f(p) = (5p +14) mod 26 (c) f(p) = (19p+ 4) mod 26 Use A = 0,B = 1,C = 2,D = 3,E = 4,F = 5,G = 6,H = 7,1 = 8, J = 9, K = 10,L = 11,M = 12,N = 13,0 = 14,P = 15,Q = 16,R = 17, S = 18, T = 19,U = 20,V = 21,W = 22,X = 23,Y = 24,Z = 25 %3D %3DEncrypt the message " MATH " by translating the letters into numbers and then applying the encryption function given, and then translating the numbers back into letters. (a) f(p) = (15p + 3) mod 26 (b) f(p) = (17p + 9) mod 26 (c) f(p) = (19p+ 4) mod 26 Use A = 0,B = 1,C = 2,D = 3,E = 4,F = 5,G = 6,H = 7,1 = 8, J = 9,K = 10,L = 11,M = 12, N = 13,0 = 14,P = 15,Q = 16,R = 17, S = 18,T = 19,U = 20,V = 21,W = 22,X = 23,Y = 24, Z = 25
- The following parameters are chosen to generate the public and private keys for the RSA cryptosystem. p = 13q = 11e = 37d = 13 If the ciphertext is c = 8, then what is the plaintext m?Suppose a message is encrypted using the RSA system with n = 53*61 and e = 19. Suppose the ciphertext message is 2701 7352 6410. Show how it is decrypted, i.e., find the secret key d and show how it is used to do the decryption. Do not calculate the modular exponentiations, only show what they should be. Thank you for your help!Determines the result of the following operations: a (7x5) (mod 6) ь. (9х 3) (mod 4) C. (12 x 11) (mod 20)
- Encode the number using the given public key. Encode the number M = 49 using the public key n = 77 and e = 37. Assume you are encoding the number using the RSA cryptosystem. Note: You can use the Modular Exponentiation calculator to help with the calculation.In the use of RSA Cryptography, for the public key (11, 65), what is the decrypted original message for ciphertext 5? You must show every step from beginning until the end for the derivation of the message.Solve the following congruences: (a) 3x 8 (mod 5)(b) 3x 8 (mod 12)