Problem Statement:Let H be a Hilbert space, and let T: HH be a normal operator with spectral measure E.Consider the dual operator T* and its spectral measure E*.1. Dual Spectral Measures: Prove that E* (B):denotes the complex conjugate of B.=E(B) for all Borel sets BCC, where B2. Measure-Theoretic Duality: Establish a duality relationship between E and E* by showing thatfor any bounded Borel measurable function f : C→ C. f(T*) = F(T)*, where F(A):f(x).=3. Spectral Pair Properties: Define what constitutes a spectral pair (E, E*) and prove that thispair satisfies certain measure-theoretic duality conditions, such as mutual absolute continuity orsingularity, based on the properties of T.Requirements:•••Explore the relationship between an operator and its adjoint in spectral terms.Utilize complex conjugation and duality in measure-theoretic contexts.Formalize and prove properties of spectral pairs within the framework of spectral theory.

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Answered: Problem Statement: Let H be a Hilbert…

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter6: Vector Spaces

Section6.2: Linear Independence, Basis, And Dimension

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Find the kernel of the linear transformation T:R4R4, T(x1,x2,x3,x4)=(x1x2,x2x1,0,x3+x4).
Let A E BL(H). Then A is called normal if A*A = AA*, uni- tary if A*A = I = AA*, that is, A* = A-¹, and self-adjoint if A* = A. Clearly, if A is unitary or self-adjoint, then A is normal. How- ever, a normal operator need be neither unitary nor self-adjoint. For example, let H = K² and for x = (x(1), x(2)) in H, A(x) = (x(1) − x(2), x(1) + x(2)). Then it can be easily seen that for x = H, A*(x) = (x(1) + x(2), −x(1) + x(2)), Request A*A(z) = 2(x(1),z(2)) = AA*(x). Hence A*A = AA*, but A*A# I and A* ‡ A. explain these steps in détail.
Let A E BL(H). Then A is called normal if A*A = AA*, uni- tary if A*A = I = AA*, that is, A* = A−¹, and self-adjoint if A* = A. Clearly, if A is unitary or self-adjoint, then A is normal. How- ever, a normal operator need be neither unitary nor self-adjoint. For example, let H = K² and for x = (x(1), x(2)) in H, A(x) = (x(1) − x(2), x(1) + x(2)). Then it can be easily seen that for x = H, A*(x) = (x(1) + x(2), −x(1) + x(2)), A*A(x) = 2(x(1), x(2)) = AA*(x). Hence A*A = AA*, but A*A ‡ I and A* # A. It is easy to see that if B is a normal operator and a C is a bounded operator such that C*C = I, then the operator A = CBC* is normal. Note that a bounded operator C may satisfy C*C = I without being a unitary operator. For example, let H = ² and for x = (x(1), x(2),...) in H, let C(x) = (0, x(1), x(2),...). 26 Normal, Unitary and Self-Adjoint Operators Then C*(x) = (x(2), x(3),…) for x € H, Hence Request explain Iin detail for better understan- 461 -ding C*C(x) = C*((0, x(1), x(2),...)) =…
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