The flowrate between tank A and tank B shown in the figure below is to be increased by 20% (i.e., from Q to 1.20Q) by the addition of second pipe (indicated by the dotted lines) running from node C to tank B. If the elevation of the free surface in tank A is 15 ft above that in tank B, determine the diameter, D, of this new pipe. Neglect minor losses and assume that the friction factor for each pipe is 0.02. 6-in. diameter; 600 ft long 6-in. diameter: 500 ft long Diameter D, 500 ft long D= ft

The flowrate between tank A and tank B shown in the figure below is to be increased by 20% (i.e., from Q to 1.20Q) by the addition of second pipe (indicated by the dotted lines) running from node C to tank B. If the elevation of the free surface in tank A is 15 ft above that in tank B, determine the diameter, D, of this new pipe. Neglect minor losses and assume that the friction factor for each pipe is 0.02. 6-in. diameter; 600 ft long 6-in. diameter: 500 ft long Diameter D, 500 ft long D= ft

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Fluid Dynamics

The study of the flow of gases and liquids, usually in and around solid surfaces, is known as fluid dynamics in physics and engineering. Fluid dynamics, for example, can be used to evaluate the movement of air through an airplane wing or the surface of a vehicle. It can also be used in ship design to increase the speed at which ships pass through water.

Question

The flowrate between tank A and tank B shown in the figure below is to be increased by 20% (i.e., from Qto 1.20Q) by the addition of a
second pipe (indicated by the dotted lines) running from node C to tank B. If the elevation of the free surface in tank A is 15 ft above
that in tank B, determine the diameter, D, of this new pipe. Neglect minor losses and assume that the friction factor for each pipe is
0.02.
6-in. diameter;
600 ft long
6-in. diameter:
500 ft long
Diameter D, 500 ft long
D =
ft

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Which of the following equations below describes the system head of the piping shown below. The total length of the pipe is 154 ft. Take the friction factor to be 0.026. The pipe used has a nominal diameter of 4 inches and Schedule No. 40. The system head H is in ft and the flow rate Q is in ft^3/s. Hint: You need to use the Tioga table and K value for minor losses. Z₂ = 107 ft Reservoir B 90° regular screwed elbow Pump Z₁ = 53 ft Reservoir A A) H=51+25.98(Q^2) B) H=54+24.98(Q^2) ⒸH=54+25.98(Q^2) ⠀
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